Calculate the boiling point, in degrees Celsius, of a solution containing 33.1 grams of CCl4 (molar mass=153.82 g/mol) and 785.4 grams of C6H6(molar mass=78.11g/mol) The molal-boiling point elevation constant for C6H6 is 2.53°C/m and pure C6H6 boils at 80.1°C.

Given mass of CCl4 = 33.1 gram molar mass of CCl4 = 153.82 gm/mole mass of C6H6…

Answered: Calculate the boiling point, in degrees…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter13: The Chemistry Of Solutes And Solutions

Section: Chapter Questions

Problem 63QRT

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Calculate the boiling point, in degrees Celsius, of a solution containing 33.1 grams of CCl₄ (molar mass=153.82 g/mol) and 785.4 grams of C₆H₆(molar mass=78.11g/mol) The molal-boiling point elevation constant for C₆H₆ is 2.53°C/m and pure C₆H₆ boils at 80.1°C.

Expert Solution

Step 1

Given

mass of CCl₄= 33.1 gram

molar mass of CCl₄= 153.82 gm/mole

mass of C₆H₆ = 785.4 gram

= 0.7854 kg

Molal boiling point elevation Constant (K_b) = 2.53 ℃/m

Boiling point of pure C₆H₆ =80.1 ℃

Boiling point of solution = ?

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