Calculate the concentration of free Zn2+ ion at equilibrium when 1.58x10-2 mol zinc sulfate is added to 1.00 L of solution that is buffered at pH 12.30. For Zn(OH)4²", Ky = 4.6x1017, [Zn2+] = M

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter17: Principles Of Chemical Reactivity: Other Aspects Of Aqueous Equilibria
Section: Chapter Questions
Problem 90GQ: What volume of 0.200 M HCl must be added to 500.0 mL of 0.250 M NH3 to have a buffer with a pH of...
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Calculate the concentration of free Zn2+ ion at equilibrium when 1.58x10-2 mol zinc sulfate is added to 1.00 L of
solution that is buffered at pH 12.30. For Zn(OH),2, K, 4.6x1017.
[Zn2+] =
M.
Transcribed Image Text:Calculate the concentration of free Zn2+ ion at equilibrium when 1.58x10-2 mol zinc sulfate is added to 1.00 L of solution that is buffered at pH 12.30. For Zn(OH),2, K, 4.6x1017. [Zn2+] = M.
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