Calculate the equivalent hydraulic conductivity for the soil profile shown in Figure k = 2.3 x 10 cm/s k, = 8 x 102 cm/s k. = 5.7 x 10 cm/s, k, = 25.5 x 10 cm/s 10 m 2 m %3D k, = 9.2 x 107 cm/s k, = 27 x 107 cm/s 10 m

Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN:9781305635180
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Braja M. Das, Nagaratnam Sivakugan
Chapter6: Hydraulic Conductivity
Section: Chapter Questions
Problem 6.14P
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1. Calculate the equivalent hydraulic conductivity for the soil profile shown in figure

 

2. An excavation is proposed for a square area near the bend of a river, as shown in figure. It is expected that the flow of water into the excavation will come through the silt layer. Pumping test reveal an average horizontal hydraulic conductivity of 2 x 10 -5 cm/s in the silt layer. The excavation has to be kept dry. Determine the flow (qs) into the excavation.

Calculate the equivalent hydraulic conductivity for the
soil profile shown in Figure
k = 2.3 x 10 cm/s
k, = 8 x 102 cm/s
k. = 5.7 x 10 cm/s, k, = 25.5 x 10 cm/s
10 m
2 m
%3D
k, = 9.2 x 107 cm/s
k, = 27 x 107 cm/s
10 m
Transcribed Image Text:Calculate the equivalent hydraulic conductivity for the soil profile shown in Figure k = 2.3 x 10 cm/s k, = 8 x 102 cm/s k. = 5.7 x 10 cm/s, k, = 25.5 x 10 cm/s 10 m 2 m %3D k, = 9.2 x 107 cm/s k, = 27 x 107 cm/s 10 m
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