Calculate the fluid force on one side of the plate using the coordinate system shown below. Assume the density is 62.4 lb/ft³ Surface of pool Depth lyl y (ft) (x,y) - 11 11 .x (ft) -----y=-2
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Formula used
Where w is density,
F is fluid force.
From figure, equation of line passing through (0,-11) and (11,0) is,
x= 11+y,
Length of strip = 2x= 22+2y.
Area of strip dA= 2x.dy
dA= 2(11+y)dy,
dP=62.4y lb/ft³
dF1=dP×dA,
dF1= 62.4y×2(11+y)dA,
dF1= 124.8(11y+y²)dA
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