Calculate the freezing point of a 0.05500 m aqueous solution of NaNO3. The molal freezing- point-depression constant of water is 1.86°C/m. (assume 100% ionization of NaNO3) my (incorrect ) answer was -.205...what did i do wrong? I assumed the m is molality not molarity. it seemed like a straight forward plug and chug. T = i * kf * m i = 2 kf = 1.86 C/m m = .05500
Calculate the freezing point of a 0.05500 m aqueous solution of NaNO3. The molal freezing- point-depression constant of water is 1.86°C/m. (assume 100% ionization of NaNO3) my (incorrect ) answer was -.205...what did i do wrong? I assumed the m is molality not molarity. it seemed like a straight forward plug and chug. T = i * kf * m i = 2 kf = 1.86 C/m m = .05500
Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.64E
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Calculate the freezing point of a 0.05500 m aqueous solution of NaNO3. The molal freezing- point-depression constant of water is 1.86°C/m. (assume 100% ionization of NaNO3)
my (incorrect ) answer was -.205...what did i do wrong? I assumed the m is molality not molarity. it seemed like a straight forward plug and chug.
T = i * kf * m
i = 2
kf = 1.86 C/m
m = .05500
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