calculate the heat of fusion (red part) given the heat capacity (83.2 Celsius) and other important data.

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter8: Thermochemistry
Section: Chapter Questions
Problem 31QAP: A student is asked to calculate the amount of heat involved in changing 10.0 g of liquid bromine at...
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calculate the heat of fusion (red part) given the heat capacity (83.2 Celsius) and other important data.

Enter the heat capacity of the calorimeter in J/°C that will be used for parts 2 and 4a. (Enter your answer to three significant figures.)
4.0 83.2
J/°C
= Heat capacity
Transcribed Image Text:Enter the heat capacity of the calorimeter in J/°C that will be used for parts 2 and 4a. (Enter your answer to three significant figures.) 4.0 83.2 J/°C = Heat capacity
O Part 2. Heat of Fusion of Ice
Record the following masses to the nearest 0.01 g.
Table 3
Mass (g)
Calorimeter
4.0 19.78
Calorimeter & Room Temperature Water 40/ 117.97
Room Temperature Water
[4.0
98.19
Calorimeter & All Water/Ice
4.0 142.92
Ice
4.0 24.95
Enter the following temperatures to the nearest 0.1°C.
Table 4
Temperature (°C)
Calorimeter & Room Temperature Water 49 19.0
Lowest Temperature Reached
4.0 6.0
Results
Calculate the heat of fusion of ice in J/g, using Eq. 12d. (Enter your answer to three significant figures.)
AH cool water + AH cool calorimeter + AHmelt ice + AH,
warmup melted ice =
m1Cwater(Tfinal - T1) + Ccalorimeter(Tfinal
T1) + mice Ahfusion, per g
+ mice Cwater(Tfinal
0°C) = 0
4.0
J/g
Some liquid water probably went into your calorimeter along with the ice. How would that affect your result?
The calculated heat of fusion would be higher than the actual.
The calculated heat of fusion would be lower than the actual.
The results would not be affected.
Transcribed Image Text:O Part 2. Heat of Fusion of Ice Record the following masses to the nearest 0.01 g. Table 3 Mass (g) Calorimeter 4.0 19.78 Calorimeter & Room Temperature Water 40/ 117.97 Room Temperature Water [4.0 98.19 Calorimeter & All Water/Ice 4.0 142.92 Ice 4.0 24.95 Enter the following temperatures to the nearest 0.1°C. Table 4 Temperature (°C) Calorimeter & Room Temperature Water 49 19.0 Lowest Temperature Reached 4.0 6.0 Results Calculate the heat of fusion of ice in J/g, using Eq. 12d. (Enter your answer to three significant figures.) AH cool water + AH cool calorimeter + AHmelt ice + AH, warmup melted ice = m1Cwater(Tfinal - T1) + Ccalorimeter(Tfinal T1) + mice Ahfusion, per g + mice Cwater(Tfinal 0°C) = 0 4.0 J/g Some liquid water probably went into your calorimeter along with the ice. How would that affect your result? The calculated heat of fusion would be higher than the actual. The calculated heat of fusion would be lower than the actual. The results would not be affected.
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