Calculate the magnetic field created by the solenoid (specifications given below) carrying a current of 0.3 A. Solenoid specifications; Length (L) = 11 cm - Coil outside diameter (D) = 3.5 cm - Number of Turns (n) = 2920 Turns per length N = (2920) / (0.11 m) Note : B= µo IN (Ho=4T10-7 T.m/A)

Calculate the magnetic field created by the solenoid (specifications given below) carrying a current of 0.3 A. Solenoid specifications; Length (L) = 11 cm - Coil outside diameter (D) = 3.5 cm - Number of Turns (n) = 2920 Turns per length N = (2920) / (0.11 m) Note : B= µo IN (Ho=4T10-7 T.m/A)

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter23: Faraday’s Law And Inductance

Section: Chapter Questions

Problem 25P

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Concept explainers

Ferromagnetism

Ferromagnetism is a mechanism by which some materials show magnetic properties. Iron and magnetite, an oxide of iron, are two naturally occurring materials that show the property of ferromagnetism. The word ferromagnetism is derived from the Latin name of iron, "Ferrum" as it was the first observed material to show such property. The property of ferromagnetism is shown by only a few substances such as iron, nickel, cobalt, and their alloys. Some transition metals and alloys of rare-earth metals also show ferromagnetism.

Question

Calculate the magnetic field created by the solenoid (specifications given below) carrying a
current of 0.3 A.
Solenoid specifications;
Length (L) = 11 cm
Coil outside diameter (D) = 3.5 cm
Number of Turns (n) = 2920
Turns per length N = (2920) / (0.11 m)
-
Note : B= µo IN (Ho=4710-7 T.m/A)
Table 4. Calculated and measured magnetic field strength at the center of solenoid
B Calculated (Gauss)
B Measured (Gauss)

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