Calculate the number of hydrogen atoms present in 12.30 x 102 dekagrams of strontiumhydrogen sulfate heptahydrate.O 2.905 x 1024O 4.011 x 1025O 1.191 x 1026O 2.905 x 1026 What is the limiting reactant in the following reaction given that you start with 15.5 g ofsodium sulfide and 12.1 g of copper(H) sulfate?sodium sulfıde reacts with copper(II) sulfate to form (you know)O sodium sulfideO copper(II) sulfateO sodium sulfateO copper(II) sulfideO not enough information

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Answered: Čalculate the number of hydrogen atoms…

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Čalculate the number of hydrogen atoms present in 12.30 x 102 dekagrams of strontium hydrogen sulfate heptahydrate.

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter9: Chemical Quantities

Section: Chapter Questions

Problem 8ALQ

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

Calculate the number of hydrogen atoms present in 12.30 x 102 dekagrams of strontium
hydrogen sulfate heptahydrate.
O 2.905 x 1024
O 4.011 x 1025
O 1.191 x 1026
O 2.905 x 1026

What is the limiting reactant in the following reaction given that you start with 15.5 g of
sodium sulfide and 12.1 g of copper(H) sulfate?
sodium sulfıde reacts with copper(II) sulfate to form (you know)
O sodium sulfide
O copper(II) sulfate
O sodium sulfate
O copper(II) sulfide
O not enough information

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