Calculate the number of moles of water from mass of water loss: (molar mass of water= 18.0153 g/mol) 2. Calculate the moles of anhydrous salt (MgSO4) from the mass of anhydrous salt: ( molar mass of magenesium sulfate is 120.366 g/mol) 3. Compare the moles of water and andydrous salt. The moles of the anhydrous salt should be smaller value. To find the number of water molecules in the hydrate, divide the moles of water by the moles of anhydrous salt (mol/H2O / mol/MgSO4). What is the closest whole number to this value? What is the formula for the hydrate? 1.  Mass of dish + lid (g)     170.06 2.  Mass of dish + lid after 1st heating (g) 170.05 3.  Mass of dish + lid after 2nd heating (g) 170.04 4.  Mass of dish + lid + hydrate (g) 174.20 5.  Mass of dish + lid + anhydrous salt after 1st heating (g) 173.83 6.  Mass of dish + lid + anhydrous salt after 2nd heating (g) 173.80

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Chapter3: Calculations With Chemical Formulas And Equaitons
Section: Chapter Questions
Problem 3.18QP: Moles within Moles and Molar Mass Part 1: a How many hydrogen and oxygen atoms are present in 1...
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1. Calculate the number of moles of water from mass of water loss: (molar mass of water= 18.0153 g/mol)

2. Calculate the moles of anhydrous salt (MgSO4) from the mass of anhydrous salt: ( molar mass of magenesium sulfate is 120.366 g/mol)

3. Compare the moles of water and andydrous salt. The moles of the anhydrous salt should be smaller value. To find the number of water molecules in the hydrate, divide the moles of water by the moles of anhydrous salt (mol/H2O / mol/MgSO4). What is the closest whole number to this value? What is the formula for the hydrate?

1.  Mass of dish + lid (g)

 

 

170.06

2.  Mass of dish + lid after 1st heating (g)

170.05

3.  Mass of dish + lid after 2nd heating (g)

170.04

4.  Mass of dish + lid + hydrate (g)

174.20

5.  Mass of dish + lid + anhydrous salt after 1st heating (g)

173.83

6.  Mass of dish + lid + anhydrous salt after 2nd heating (g)

173.80

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