Calculate the pH at 25 °C of a 0.52 M solution of lidocaine HCl (C14H21 NONH,CI). Note that lidocaine (C14H2,NONH) is a weak base with apk, of 7.94. Round your answer to 1 decimal place. pH = |

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A: Methylamine is a weak base and in water, it reacts in the following manner, CH3NH2 + H2O ↔CH3NH3+ +…

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A: Answer:  9.66 Weak base can't dissociate completely, it's  pOH = 1/2 (PKb - logC)

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Q: Calculate the plf of a solution that is prepared by dissolving 0.520 mol of hydrocyanie acid (HCN,…

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Q: The pH of a 0.052M solution of acrylic acid (HC,H,CO,) is measured to be 2.77. Calculate the acid…

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Q: A solution is prepared at 25 °C that is initially 0.21 M in benzoic acid (HC H,CO,), a weak acid…

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Q: In the laboratory, a general chemistry student measured the pH of a 0.441 M aqueous solution of…

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Q: In the laboratory, a general chemistry student measured the pH of a 0.423 M aqueous solution of…

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