Calculate the pOH after addition of 15.66 mL of 0.1621 M HBr to 25.00 mL of 0.1546 M CH3NH2. Kb(CH3NH2) = 3.700e-4.

Chemistry
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Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 81E: Which of the indicators in Fig. 14-8 could be used for the titrations in Exercises 61 and 63?
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Calculate the pOH after addition of 15.66 mL of 0.1621 M HBr to 25.00 mL of 0.1546 M CH3NH2. Kb(CH3NH2) = 3.700e-4.

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