Use the Kinematic Equations for Projectile Motion to answer thefollowing problems.calculate the required parts.INCOMINGYou willneedto rearrangeformulastoAn Olympic long jumper leaps with an initia1 horizontal velocity of 6 m/s and an initial vertical#2velocity of 4.5 m/s.CALCULATIONSKnownsHow long was the jumper in the air? HINT: Use: v = v + gt (how long did ittake the jumper to reach the ground from her highest point?)(w/units)AADD TEXTtas.3Yo=ADD TEXTB What was the maximum height of the jump?0.920.99 metersVy =C How far was the jump?Vyo =-9.85.52

Name: Use the Kinematic Equations for Projectile Motion to answer thefollow
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Description: Use the Kinematic Equations for Projectile Motion to answer thefollowing problems.calculate the required parts.INCOMINGYou willneedto rearrangeformulastoAn Olympic long jumper leaps with an initia1 horizontal velocity of 6 m/s and an initial vertica

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calculate the required parts. An Olympie long jumper leaps with an initial horizontal velocity of6 m/s and an initial vertical velocity of 4.5 /s. $2 CALCULATIONS Knowns gt (how long did it How long was the jumper in the air? HINT: Use: v = v A take the jumper to reach the ground from her highest point?) (w/units) ADO TEXT y= Yo" ADD TEXT B What was the maximum height of the jump? 0.99 meters - Fa C How far was the jump? Vyo= 5.52

calculate the required parts. An Olympie long jumper leaps with an initial horizontal velocity of6 m/s and an initial vertical velocity of 4.5 /s. $2 CALCULATIONS Knowns gt (how long did it How long was the jumper in the air? HINT: Use: v = v A take the jumper to reach the ground from her highest point?) (w/units) ADO TEXT y= Yo" ADD TEXT B What was the maximum height of the jump? 0.99 meters - Fa C How far was the jump? Vyo= 5.52

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter2: Vectors

Section: Chapter Questions

Problem 81AP: If the velocity vector of a polar bear is u=(-18.0 i -13.0 j)km/h , how fast and in what geographic...

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