Calculate the terminal voltage for a battery with an internal resistance of 0.950 SN and an emf of 3.70 V when the battery is connected in series with an 79.8 N resistor.

College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter20: Electric Current, Resistance, And Ohm's Law
Section: Chapter Questions
Problem 14CQ: The power dissipated in a resistor is given by P = V2/R, which means power decreases if resistance...
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Part A
Calculate the terminal voltage for a battery with an internal resistance of 0.950 N and an emf of 3.70 V when the battery is connected in series with an 79.8 N resistor.
Πνα ΑΣφ
Vab =
V
国
Transcribed Image Text:Part A Calculate the terminal voltage for a battery with an internal resistance of 0.950 N and an emf of 3.70 V when the battery is connected in series with an 79.8 N resistor. Πνα ΑΣφ Vab = V 国
Part B
Calculate the terminal voltage for a battery with an internal resistance of 0.950 SN and an emf of 3.70 V when the battery is connected in series with an 798 N resistor.
V AEO
Vah =
V
Transcribed Image Text:Part B Calculate the terminal voltage for a battery with an internal resistance of 0.950 SN and an emf of 3.70 V when the battery is connected in series with an 798 N resistor. V AEO Vah = V
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