Calculate the work for the expansion of 3 moles of B,H; at 40°C from 2.74 L to 3.89 L using van der correction for intermolecular forces (a) is 6.048 bar L'/mol" and the adjustment factor of the volum The general equation for van der Waals is written below: RT A. 2352.2376 J B. -2352.2376 J C. 2118.1071J D. -2118.1071J

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Chapter21: The Kinetic Theory Of Gases
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Use integration in answering this problem. Work is equal to the integral of pressure in terms of volume from V1 to V2

 

5. Calculate the work for the expansion of 3 moles of B;Hs at 40"C from 2.74 L to 3.89 L using van der Waals equation. The
correction for intermolecular forces (a) is 6.048 bar L?/mol and the adjustment factor of the volume (b) is 0.07437 L/mol.
The general equation for van der Waals is written below:
+ a
=.
A. 2352.2376J
B. -2352.2376 J
C. 2118.1071J
D. -2118.1071 J
Transcribed Image Text:5. Calculate the work for the expansion of 3 moles of B;Hs at 40"C from 2.74 L to 3.89 L using van der Waals equation. The correction for intermolecular forces (a) is 6.048 bar L?/mol and the adjustment factor of the volume (b) is 0.07437 L/mol. The general equation for van der Waals is written below: + a =. A. 2352.2376J B. -2352.2376 J C. 2118.1071J D. -2118.1071 J
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