Calculating the Work You Do to Push a Lawn Mower Across a Large Lawn How much work is done on the lawn mower by the person in Figure 7.2(a) if he exerts a constant force of 75.0 N at an angle 35⁰ below the horizontal and pushes the mower 25.0 m on level ground? Convert the amount of work from joules to kilocalories and compare it with this person's average daily intake of 10,000 kJ (about 2400 kcal) of food energy. One calorie (1 cal) of heat is the amount required to warm 1 g of water by 1°C, and is equivalent to 4.186 J, while one food calorie (1 kcal) is equivalent to 4186 J.

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Activity 4.1

Topic: Calculating the Work You Do to Push a Lawn Mower Across a Large Lawn 

Answer the following showing the complete step-by-step process/solution. (Hint for Answer: 1.53 x 10-4)

d
(b)
F cos 8
(d)
F cos 0
F
d=0
W = Fd cos 0
d
(a)
0 = 90°
cos 8 = 0
d
Electric
generator
Ⓡ
Transcribed Image Text:d (b) F cos 8 (d) F cos 0 F d=0 W = Fd cos 0 d (a) 0 = 90° cos 8 = 0 d Electric generator Ⓡ
Calculating the Work You Do to Push a Lawn Mower Across a Large Lawn
How much work is done on the lawn mower by the person in Figure 7.2(a) if he exerts a constant force of 75.0 N at an angle 35°
below the horizontal and pushes the mower 25.0 m on level ground? Convert the amount of work from joules to kilocalories and
compare it with this person's average daily intake of 10,000 kJ (about 2400 kcal) of food energy. One calorie (1 cal) of heat is
the amount required to warm 1 g of water by 1°C, and is equivalent to 4.186 J, while one food calorie (1 kcal) is equivalent to
4186 J.
Transcribed Image Text:Calculating the Work You Do to Push a Lawn Mower Across a Large Lawn How much work is done on the lawn mower by the person in Figure 7.2(a) if he exerts a constant force of 75.0 N at an angle 35° below the horizontal and pushes the mower 25.0 m on level ground? Convert the amount of work from joules to kilocalories and compare it with this person's average daily intake of 10,000 kJ (about 2400 kcal) of food energy. One calorie (1 cal) of heat is the amount required to warm 1 g of water by 1°C, and is equivalent to 4.186 J, while one food calorie (1 kcal) is equivalent to 4186 J.
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