cos X-4 da Cos X

Q: sin x .2 3 + Cos X

A: Given: ∫sinx3+cos2xdx

Q: cos-1 (cosx)= x       where..............

A: Given, cos-1cos x=x

Q: cos( – x) + tan( – x)sin( – 2)

A:

Q: cos (2x) dx sinx+cosx COS Evaluate:

A: the given integral is: ∫cos(2x)sinx+cosxdx we have to evaluate the given integral.

Q: COS X 3) sec x + tan x = 1 - sin x

A:

Q: y- y' cos x = y² cos x (1 - sin x)

A:

Q: sin x cos x-1 %3D COs x+1 sin x

A: sin xcos x +1+cos x -1sinx=0

Q: sin( – x) = cos x = COS X

A: Given: To prove that sin(π2-x)=cos x

Q: cos sin + cos -1 x=0 %3D

A: Solve by trigonometry

Q: cos e cos 0-sin² 0 csce 5. csce-tan e II

A:

Q: cos x = 1/2 Find x

A:

Q: sin* x – cos* x = 1 x – cos? x

A:

Q: sin“ x - cos+ x = sin? x cos?

A: We will solve the problem

Q: cos(x + y) cos(x – y) = cos² x – sin² y

A: The objective of the question is proving trigonometric identities.

Q: cos x х dx /sin x COS

A:

Q: sin(x) cos(x) xp (cos(x))2

A:

Q: 10.) cos*x

A:

Q: y = 7 cos(x), y = 7 - 7 cos(x), 0 ≤ x ≤ π

A: The given equations are: y=7cosx, y=7-7cosx, 0≤x≤π To find the area of the region between the curves…

Q: | cos xV 1 + cos x dx, -ㅠ <xSㅠ.

A: Given:   By part formula of integration: Here,  and and

Q: sin x cos x 15) Simplify: csc x sec x A) 0 C) tan(x) В) 2 D) 1

A:

Q: cos² x 3D1-tan x cos x 1+ sin x

A:

Q: (cos x-1)(1+cos(-x))=-sin' x

A: cosx-11+cos-x=-sin2x

Q: cos(2 + x () 2 + cos x

A:

Q: + sin(x) = cos(x) 4x²

A: Concept:

Q: Differentiate

A: Given: the function

Q: sin Cabo-0 Jo tan (180-0). COS (180+x). (sIn?3C +COS?C)

A: We have to find: sin(360∘-x) ×tan(180∘-x)cos(180∘+x)(sin2x+cos2x)

Q: cos?x- 3 cos x =- 1 on the interval [0,1).

A: Given- 2cos2x-3cosx=-1  To find- the value of x on the interval [0,π) Concept Used- The above…

Q: Find

A:

Q: Cos z+1 cos 2 1 + sec x =

A: Use simple trigonometry relation.

Q: cos x 1) sin'x

A: “Since you have asked multiple question, we will solve the first question for you. If youwant any…

Q: Solve y'-y cosx = cos x

A: We now solve the differential equation, y' -ycosx=cosx . This is a first order homogeneous equation.

Q: sin x 6. Evaluate dx. 3 cos x

A:

Q: cos“ x sin x – sin x = 0

A: Trigonometric equation

Q: (sin(x) + cos(x))² = 1 + 2 sin(x) cos(x)

A: Topic-trigonometry identities

Q: sin x − 1 = cos x − 1

A:

Q: /(sin x+cos

A: We have to simplify of the given expression using the trigonometry formula

Q: cos 2 -x) + cos? cos? x CSC X

A:

Q: cos x cot x 1 csc x - 1 - sin x 4.

A:

Q: cos x+ coS x= 1

A: Definition used -               Solution of trigonometric equations -              If there is a…

Q: cos'x Evaluate : 3/5 sin' x( sin' x+ cos x)

A: Integration of the given expression  is :-

Q: y" - y = 10 cos x cosh x

A: Differential equations

Q: sin x COS I 2. 1+ sin(2x)

A: Use the following trigonometry formula:-  (i)  1 = sin2x + cos2x  (ii)  sin(2x) = 2sinxcosx

Q: (sin x +cos x)^2 =1+sin x cos x

A:

Q: cos (x+ y) cos (x-y) cos2 x- sin2 y

A:

Q: sin x – cos x 1+ sin(2x)

A:

Q: cos(x)+sin(x)tan(x)

A:

Q: I+ Sin X COSX 32see* COS X + Sin X

A: This problem can be solved by simplification through trigonometric identities.

Q: Solve y' + cos(x) y = cos(x).

A:

Q: cosx sec? x + cos x csc² csc² x csc² x secx cos? x cos x cos x , then 6 f(x)dx_, * f(x) 1

A: