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Asked Nov 12, 2019
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Expert Answer

Step 1

Refer to the question we have to find the intervals on which the provided function is concave up or concave down .

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f(x)-In(3x +1

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Step 2

To find that first find the inflection points, it is that point in the graph where the second derivative changes the sign or where concavity of the function changes.

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if f"(x)>Othen f(x) conceve upward if f"(x)<O then f(x) concave dowmward

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Step 3

So find the inflecti...

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f(x)= -In(3x2 +1 Find inflection point as f"(x)0 6x f'== 3x2 6(-3x2 +1) f"= =0 (3x2+1) So, 6(-3x2 +1)=0

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Calculus

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