1. The system in right figure consists of a water reservoir with a layer of compressed air above the water and a large pipe and nozzle. The pressure of the air is 50 psig, and the effects of friction can be neglected. What is the velocity of the water flowing out through the nozzle? 50 psig 30 ft

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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can you please solve question 1

 

1. The system in right figure consists of a water reservoir with a
layer of compressed air above the water and a large pipe and nozzle.
The pressure of the air is 50 psig, and the effects of friction can be
neglected. What is the velocity of the water flowing out through the
nozzle?
50 psig
2. The tank in right figure is cylindrical and has a vertical axis. Its
horizontal cross-sectional area is 100 ft². The hole in the bottom has
a cross-sectional area of 1 ft². The interface between the gasoline and the
water remains perfectly horizontal at all times. That interface is now 10 ft
above the bottom. How soon will gasoline start to flow out the bottom?
Assume frictionless flow.
30 ft
10 ft
10 ft
1
Gasoline
Water
iiili
Transcribed Image Text:1. The system in right figure consists of a water reservoir with a layer of compressed air above the water and a large pipe and nozzle. The pressure of the air is 50 psig, and the effects of friction can be neglected. What is the velocity of the water flowing out through the nozzle? 50 psig 2. The tank in right figure is cylindrical and has a vertical axis. Its horizontal cross-sectional area is 100 ft². The hole in the bottom has a cross-sectional area of 1 ft². The interface between the gasoline and the water remains perfectly horizontal at all times. That interface is now 10 ft above the bottom. How soon will gasoline start to flow out the bottom? Assume frictionless flow. 30 ft 10 ft 10 ft 1 Gasoline Water iiili
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can u explain to me why this solution isnt correct?

=
Open to atmosphere → P₁ P₂ so 0
Velinlet = 0 (not given)
V² P2
2 P
P₁
P
+ gz₁ +
0 +
(P₂ - P₁), (V2 - V²)
+
2
P
V2
2
=
V2
2
+ gz₂ + + Friction
V2
2
+ g(0-z₁) = 0
V2(water) = √2g2₁
=gz₁ where z₁ =
=
+ g(²₂-²₁) = 0
2 *
32.2ft
S²
10ft
20ft
=
25.38ft
S
Transcribed Image Text:= Open to atmosphere → P₁ P₂ so 0 Velinlet = 0 (not given) V² P2 2 P P₁ P + gz₁ + 0 + (P₂ - P₁), (V2 - V²) + 2 P V2 2 = V2 2 + gz₂ + + Friction V2 2 + g(0-z₁) = 0 V2(water) = √2g2₁ =gz₁ where z₁ = = + g(²₂-²₁) = 0 2 * 32.2ft S² 10ft 20ft = 25.38ft S
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