Can you explain why there is value of Iy. This figure the ly placed on the centroid, but correct me or please correct me why there is value of Iy instead zero value. Thank you The W section is reinforced at top and bottom flanges by a 250 mmwide by 16 mm thick plate is used as a column with with a length of5.0 m. Determine the safe axial load the column can carry usingAISC specifications with Fy = 345 MPa when:a) column ends are fixedb) one end of the column is fixed; the hingedc) both ends are hinged 200 mmCIVIL ENGINEERINGSTEEL DESIGNtw13.41= 8.08mm250 mm Iminimum is Iyy sJyyIyyPart @) lahenJeffP =Safe axialP =PPart bleffP[16x30²] + 2x [1341 x Jan ²] +191.18 X 8.08³250X 2001259.55 x 106mm 4column endsP=IgloadTL 2 EI minTTP =Both endleffP =-Oneleffпяхах 105 х25J18807, 51 KN2x 10 x 59.55 X10(2500)end of theare(4000)1346.88 KN0.80 x 5 =T2X105X 59.55 X 106l=are2500mmHingedcolumn is fixed the hinged.4000 mmfixed5000mmпя хохло 5 х 59.55 х106(5000)4701. 87KN

The solution of steel column capacity is given as above as per AISC Specifications. Now the question…

Answered: Can you explain why there is value of…

Can you explain why there is value of Iy. This figure the ly placed on the centroid, but correct me or please correct me why there is value of Iy instead zero value. Thank you

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter10: Plate Girders

Section: Chapter Questions

Problem 10.7.8P

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Question

Can you explain why there is value of Iy. This figure the ly placed on the centroid, but correct me or please correct me why there is value of Iy instead zero value. Thank you

The W section is reinforced at top and bottom flanges by a 250 mm
wide by 16 mm thick plate is used as a column with with a length of
5.0 m. Determine the safe axial load the column can carry using
AISC specifications with Fy = 345 MPa when:
a) column ends are fixed
b) one end of the column is fixed; the hinged
c) both ends are hinged 200 mm
CIVIL ENGINEERING
STEEL DESIGN
tw
13.41
= 8.08mm
250 mm

Iminimum is Iyy s
Jyy
Iyy
Part @) lahen
Jeff
P =
Safe axial
P =
P
Part b
leff
P
[16x30²] + 2x [1341 x Jan ²] +191.18 X 8.08³
250
X 200
12
59.55 x 106mm 4
column ends
P
=
I
g
load
TL 2 EI min
TT
P =
Both end
leff
P =
-
One
leff
пяхах 105 х
2
5
J
18807, 51 KN
2x 10 x 59.55 X10
(2500)
end of the
are
(4000)
1346.88 KN
0.80 x 5 =
T2X105X 59.55 X 106
l=
are
2500mm
Hinged
column is fixed the hinged.
4000 mm
fixed
5000mm
пя хохло 5 х 59.55 х106
(5000)
4701. 87KN

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