case there are at least two lines with equivalent worth in this segment, their overall request doesn't change (such arranging calculations are called stable).    You can find this conduct of arranging by section in numerous office programming for overseeing accounting pages. Petya works in one, and he has a table An opened at the present time. He needs to perform zero of

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
Section: Chapter Questions
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Correct answer will be upvoted else downvoted. Computer science.

 

 case there are at least two lines with equivalent worth in this segment, their overall request doesn't change (such arranging calculations are called stable). 

 

You can find this conduct of arranging by section in numerous office programming for overseeing accounting pages. Petya works in one, and he has a table An opened at the present time. He needs to perform zero of more sortings by segment to change this table to table B. 

 

Decide whether it is feasible to do as such, and if indeed, find an arrangement of segments to sort by. Note that you don't have to limit the number of sortings. 

 

Input 

 

The principal line contains two integers n and m (1≤n,m≤1500) — the measures of the tables. 

 

Every one of the following n lines contains m integers ai,j (1≤ai,j≤n), meaning the components of the table A. 

 

Every one of the following n lines contains m integers bi,j (1≤bi,j≤n), indicating the components of the table B. 

 

Output 

 

In case it is absurd to expect to change An into B, print −1. 

 

In any case, first print an integer k (0≤k≤5000) — the number of sortings in your answer. 

 

Then, at that point, print k integers c1,… ,ck (1≤ci≤m) — the segments, by which Petya needs to play out an arranging.

 

 

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