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- A composite beam is fabricated by bolting two 3.2-in-wide by 10-in.-deep timber planks to the sides of a 0.4-in. by 10-in. steel plate. The moduli of elasticity of the timber and the steel are 1660 ksi and 28900 ksi, respectively. The simply supported beam spans a distance of 17 ft and carries two concentrated loads P, which are applied as shown. Assume LAB = LCD = 4 ft, LBC = 9 ft, b = 3.2 in., d = 10 in. and t = 0.4 in. (a) Determine the maximum bending stresses 07, os produced in the timber planks and the steel plate if P = 3.7 kips. (b) Assume that the allowable bending stresses of the timber and the steel are 1130 psi and 18000 psi, respectively. Determine the largest acceptable magnitude for concentrated loads P. (You may neglect the weight of the beam in your calculations.)A composite beam is fabricated by bolting two 3.2-in.-wide by 10-in.-deep timber planks to the sides of a 0.4-in. by 10-in. steel plate. The moduli of elasticity of the timber and the steel are 1660 ksi and 28900 ksi, respectively. The simply supported beam spans a distance of 17 ft and carries two concentrated loads P, which are applied as shown. Assume LAB = LCD= 4 ft, Lec = 9 ft, b = 3.2 in., d = 10 in. and t = 0.4 in. (a) Determine the maximum bending stresses Ot, os produced in the timber planks and the steel plate if P = 3.7 kips. (b) Assume that the allowable bending stresses of the timber and the steel are 1130 psi and 18000 psi, respectively. Determine the largest acceptable magnitude for concentrated loads P. (You may neglect the weight of the beam in your calculations.)A reinforced rectangular beam with width b and effective depth d has 4.16 mm bars placed on 1 layer at the tension side. The beam has a stirrup with a diameter of 10 mm. Use fc=28 Mpa and fy=420 MPa GIVEN: b= 350 mm d= 600 mm L= 6 m Wd = 13 kN/m WL = 36 kN/m Calculate the nominal moment capacity of the beam Calculate that strain of the tension bars. Calculate the strength reduction factor of the beam
- A wood beam AB on simple supports with spanlength equal to 10 ft is subjected to a uniform load ofintensity 125 lb/ft acting along the entire length of thebeam, a concentrated load of magnitude 7500 lb acting ata point 3 ft from the right-hand support, and a momentat A of 18,500 ft-lb (see figure). The allowable stresses inbending and shear, respectively, are 2250 psi and 160 psi.(a) From the table in Appendix G, select the lightestbeam that will support the loads (disregard theweight of the beam).(b) Taking into account the weight of the beam(weight density = 35 lb/ft3 ), verify that theselected beam is satisfactory, or if it is not, selecta new beam.Compute Nominal Moment Capacity of the following L beam Slab (flange) thickness = 4 in. Center to center distance of web = 13 ft. Web width = 12 in. Total thickness (flange + web) = 26 in. Depth, d = 22 in. dt = 23 in. Reinforcement 6- # 7 bars. Compressive strength = 4500 psi. Yield strength of steel = 60000 psi. Span = 25 ft. ACI CodeThe beam shown here is made of wood with an allowable shear stress of τall = 1100 psi. If PB = 5 kips, determine the maximum allowable force PC that can be applied on the structure before the beam fails in shear.[LAB= 2 ft, LBC= 2 ft, LCD= 1.5 ft, b = 1.25 in., h = 7 in.] Determine the maximum value of the first moment of area (Q) for the beam. (in^3) Determine the maximum allowable force at C (PC) that can be applied on the structure before it fails in shear. (kips)
- Situation 11 An overhang beam is loaded as shown below. The beam cross-section was built by attaching two (2) channels to a 9mm thick plate using 16mm rivets The property of the channel is given below: Depth, D=225 mm Flange Width, B=112.5 mm. Flange Thickness, tf=9mm Web Thickness, tw9 mm The allowable flexural stress on the beam is 180 MPa. Rivets has a capacity of t 100 MPa on shear, for bearing, o.-200 MPa on single sheer, a-260MPa on double shear. 2. Determine the moment of inertia, I, of the section in mm^4.Situation 11 An overhang beam is loaded as shown below. The beam cross-section was built by attaching two (2) channels to a 9mm thick plate using 16mm rivets The property of the channel is given below: Depth, D=225 mm Flange Width, B=112.5 mm. Flange Thickness, tf=9mm Web Thickness, tw9 mm The allowable flexural stress on the beam is 180 MPa. Rivets has a capacity of t 100 MPa on shear, for bearing, o.-200 MPa on single sheer, a-260MPa on double shear. Determine the maximum flexural stress on the beam in MPa. Determine the maximum shearing stress on the beam in MPa.Situation 11 An overhang beam is loaded as shown below. The beam cross-section was built by attaching two (2) channels to a 9mm thick plate using 16mm rivets The property of the channel is given: Depth, D=225 mm Flange Width, B=112.5 mm. Flange Thickness, tf=9mm Web Thickness, tw9 mm The allowable flexural stress on the beam is 180 MPa. Rivets has a capacity of t 100 MPa on shear, for bearing, o.-200 MPa on single sheer, a-260MPa on double shear Determine the location of centroid, y, from top of the beam in mm Determine the moment of inertia, I, of the section in mm^4. Determine the maximum allowable moment, M(all) in kn-m, base on the beam's cross-section. Determine the location of the maximum moment on the beam in meters. Determine the maximum moment, in kN-m, on the beam Determine the maximum flexural stress on the beam in MPa.
- b. A steel tape is 30m long under a standard pull of 6kg with a constant cross-sectional area of 0.05cm2 . If the normal tension applied to make the tape equal to its nominal length when supported only at the end points, that is the effect of sag will be eliminated by the elongation of the tape due to the application of this load is equal to 16kg. Determine the unit weight of the tape. Modulus of elasticity of tape is 2x106 kg/cm2 .A composite beam is fabricated by bolting two 2.3-in-wide by 14-in-deep timber planks to the sides of a 0.5-in. by 14-in. steel plate The moduli of elasticity of the timber and the steel are 1510 ksi and 31300 ksi, respectively. The simply supported beam spans a distance of 17 ft and carries two concentrated loads P. which are applied as shown. Assume LAB =LCD=4f L BC =9ft, b = 23in d = 14 in, and t = 0.5in (a) Determine the maximum bending stresses a,, a, produced in the timber planks and the steel plate if P-2.8 kips. (b) Assume that the allowable bending stresses of the timber and the steel are 1210 psi and 19500 psi, respectively. Determine the largest acceptable magnitude for concentrated loads P. (You may neglect the weight of the beam in your calculations.)•Timber beamSafe working stress = 25 MPaCross-section dimensions:height = 119 mm,width = 66 mmProving ring number 293. Steel beam Safe working stress = 200 MPa Cross-section dimensions:external height = 149 mm,external width = 50 mm,wall thickness = 3.0 mm,Proving ring number 1522.1)Calculate safe max bending moment in the central part of the beam using Mmax = (I)(max stress)/(D/2)2) calculate Safe applied force in the proving ring or tie rod, assuming a symmetrical setup as in the photowith a ‘lever arm’ of 600 mm