Determine the structure. Note that for the 13C data, multiplicity is given. So a CH3 group would be a quartet (n+1) and a CH2 group would be a triplet, etc CH14013C NMR:1Η ΝMR:29.7, t29.8, q (3)46.4, s60.0, t0.91, s, 9H1.53, t, J = 7.3 Hz, 2H2.13, bs, lH (exchanges)3.70, t, J = 7.3 Hz, 2HCH10013C NMR:'H NMR:23.5, t26.7, t (2)68.9, t (2)1.7, m, 6H3.72, t, J = 7.4 Hz, 4HlimPPhaAC12H140213C NMR:'H NMR:2.27, s, 3H27.2, q68.8, t72.9, t4.20, d, J = 4.5 Hz, 2H4.57, s, 2H127.7, d (2)127.9, d6.35, d, J = 16.1 Hz, IH6.80, dt, J= 16.1, 4.5 Hz, IH7.3, m, 5H128.5, d (2)130.4, d137.6, s142.9, d198.0, s

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Answered: CH140 13C NMR: 1Η ΝMR: 29.7, t 29.8, q…

CH140 13C NMR: 1Η ΝMR: 29.7, t 29.8, q (3) 46.4, s 60.0, t 0.91, s, 9H 1.53, t, J = 7.3 Hz, 2H 2.13, bs, IH (exchanges) 3.70, t, J = 7.3 Hz, 2H

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter13: Structure Determination: Nuclear Magnetic Resonance Spectroscopy

Section13.SE: Something Extra

Problem 29AP

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Concept explainers

Applications of Molecular Spectroscopy

When light sources pass through the diffraction grating then light splits into different wavelengths. The light source produces two types of patterns that are shown as destructive and non-destructive. The light source is in the form of quanta that is quantitation.

Question

Determine the structure. Note that for the ¹³C data, multiplicity is given. So a CH₃ group would be a quartet (n+1) and a CH₂ group would be a triplet, etc

CH140
13C NMR:
1Η ΝMR:
29.7, t
29.8, q (3)
46.4, s
60.0, t
0.91, s, 9H
1.53, t, J = 7.3 Hz, 2H
2.13, bs, lH (exchanges)
3.70, t, J = 7.3 Hz, 2H
CH100
13C NMR:
'H NMR:
23.5, t
26.7, t (2)
68.9, t (2)
1.7, m, 6H
3.72, t, J = 7.4 Hz, 4H
lim
PPha
A
C12H1402
13C NMR:
'H NMR:
2.27, s, 3H
27.2, q
68.8, t
72.9, t
4.20, d, J = 4.5 Hz, 2H
4.57, s, 2H
127.7, d (2)
127.9, d
6.35, d, J = 16.1 Hz, IH
6.80, dt, J= 16.1, 4.5 Hz, IH
7.3, m, 5H
128.5, d (2)
130.4, d
137.6, s
142.9, d
198.0, s

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