) CH4(g) + 2O2(g) ↔ CO2(g) + 2H2O(g) a) Write the equilibrium expression for the reaction above. b) Calculate the value of Keq given the following equilibrium conditions. Show all work. CH4 = 0.10M O2 = 0.20M CO2 = 1.5M H2O = 3.0M c) Based on your answer to part b), what does the value of Keq tell you about what the reaction favors at equilibrium & explain how can you tell?
) CH4(g) + 2O2(g) ↔ CO2(g) + 2H2O(g) a) Write the equilibrium expression for the reaction above. b) Calculate the value of Keq given the following equilibrium conditions. Show all work. CH4 = 0.10M O2 = 0.20M CO2 = 1.5M H2O = 3.0M c) Based on your answer to part b), what does the value of Keq tell you about what the reaction favors at equilibrium & explain how can you tell?
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 2RQ: What is the law of mass action? Is it true that the value of K depends on the amounts of reactants...
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1)
CH4(g) + 2O2(g) ↔ CO2(g) + 2H2O(g)
a) Write the equilibrium expression for the reaction above.
b) Calculate the value of Keq given the following equilibrium conditions. Show all work.
CH4 = 0.10M O2 = 0.20M CO2 = 1.5M H2O = 3.0M
c) Based on your answer to part b), what does the value of Keq tell you about what the reaction favors at equilibrium & explain how can you tell?
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