Chapter 09, Problem 007 In the ammonia (NH3) molecule of the figure, three hydrogen (H) atoms form an equilateral triangle, with the center of the triangle at distance d = 9.40 x 10-11 m fre each hydrogen atom. The nitrogen (N) atom is at the apex of a pyramid, with the three hydrogen atoms forming the base. The nitrogen-to-hydrogen atomic mass rati 13.9, and the nitrogen-to-hydrogen distance is L = 10.14 x 10-11 m. What are the (a) x and (b) y coordinates of the molecule's center of mass? I.

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Chapter14: Fluid Mechanics
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Chapter 09, Problem 007
In the ammonia (NH3) molecule of the figure, three hydrogen (H) atoms form an equilateral triangle, with the center of the triangle at distance d = 9.40 x 10-11 m from
each hydrogen atom. The nitrogen (N) atom is at the apex of a pyramid, with the three hydrogen atoms forming the base. The nitrogen-to-hydrogen atomic mass ratio is
13.9, and the nitrogen-to-hydrogen distance is L = 10.14 x 10-11 m. What are the (a) x and (b) y coordinates of the molecule's center of mass?
1.
d.
(a) Number
Units
(b) Number
Units
Transcribed Image Text:Chapter 09, Problem 007 In the ammonia (NH3) molecule of the figure, three hydrogen (H) atoms form an equilateral triangle, with the center of the triangle at distance d = 9.40 x 10-11 m from each hydrogen atom. The nitrogen (N) atom is at the apex of a pyramid, with the three hydrogen atoms forming the base. The nitrogen-to-hydrogen atomic mass ratio is 13.9, and the nitrogen-to-hydrogen distance is L = 10.14 x 10-11 m. What are the (a) x and (b) y coordinates of the molecule's center of mass? 1. d. (a) Number Units (b) Number Units
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