Chapter 10, Problem 053Your answer is partially correct. Try again.The figure shows a uniform disk that can rotate around its center like a merry-go-round. The disk hasinitially at rest. Starting at time t 0, two forces are to be applied tangentially to the rim as indicated, so that at time t = 1.2 s the disk has an angularvelocity of 210 rad/s counterclockwise. Force F1 has a magnitude of 0.0958 N. What is magnitude F2?radius of 2.0 cm and a mass of 24 grams and isNumberTo.120UnitsTNUse correct number of significant digits; the tolerance is +/-2%

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Chapter 10, Problem 053
Your answer is partially correct. Try again.
The figure shows a uniform disk that can rotate around its center like a merry-go-round. The disk has
initially at rest. Starting at time t 0, two forces are to be applied tangentially to the rim as indicated, so that at time t = 1.2 s the disk has an angular
velocity of 210 rad/s counterclockwise. Force F1 has a magnitude of 0.0958 N. What is magnitude F2?
radius of 2.0 cm and a mass of 24 grams and is
NumberTo.120
Units
TN
Use correct number of significant digits; the tolerance is +/-2%
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Chapter 10, Problem 053 Your answer is partially correct. Try again. The figure shows a uniform disk that can rotate around its center like a merry-go-round. The disk has initially at rest. Starting at time t 0, two forces are to be applied tangentially to the rim as indicated, so that at time t = 1.2 s the disk has an angular velocity of 210 rad/s counterclockwise. Force F1 has a magnitude of 0.0958 N. What is magnitude F2? radius of 2.0 cm and a mass of 24 grams and is NumberTo.120 Units TN Use correct number of significant digits; the tolerance is +/-2%

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Expert Answer

Step 1

The moment of inertia of a disc is

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102 m 2cm 103 kg 24 g 1g 1cm =4.8x10- kg m

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Step 2

Net force acting on the system is

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= Ia Fr-Fr I (I)

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Step 3

Rearrange (II) in terms of ...

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t F= 210rad/s +(0.0958 N) (2:10 m 4.8x10 kg m2 1.2s 2x10 m =0.1378 N

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