Cerium(IV) sulfate is used to titrate a solution of tin(II) ions, with which it reacts according to 2ce4+ (aq) + Sn²(aq)2Ce³(aq) + Sn**(aq) A cerium(IV) sulfate solution is prepared by dissolving 39.77 g of Ce(SO4)2 in water and diluting to a total volume of 1.000 L. A total of 15.83 mL of this solution is required to reach the endpoint in a titration of a 100.0-ml sample containing Sn²* (aq). Determine the concentration of Sn²* in the original solution. M
Cerium(IV) sulfate is used to titrate a solution of tin(II) ions, with which it reacts according to 2ce4+ (aq) + Sn²(aq)2Ce³(aq) + Sn**(aq) A cerium(IV) sulfate solution is prepared by dissolving 39.77 g of Ce(SO4)2 in water and diluting to a total volume of 1.000 L. A total of 15.83 mL of this solution is required to reach the endpoint in a titration of a 100.0-ml sample containing Sn²* (aq). Determine the concentration of Sn²* in the original solution. M
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Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.84QP: A soluble iodide was dissolved in water. Then an excess of silver nitrate, AgNO3, was added to...
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Transcribed Image Text:Cerium(IV) sulfate is used to titrate a solution of tin(II) ions, with which it reacts according to
2ce4+ (aq) + Sn²(aq)2Ce³(aq) + Sn**(aq)
A cerium(IV) sulfate solution is prepared by dissolving 39.77 g of Ce(SO4)2 in water and diluting to a total volume of 1.000 L. A total
of 15.83 mL of this solution is required to reach the endpoint in a titration of a 100.0-ml sample containing Sn²* (aq). Determine the
concentration of Sn²* in the original solution.
M
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