Asked Dec 17, 2019

Chinook salmon are able to move upstream faster by
jumping out of the water periodically; this behavior is called
porpoising. Suppose a salmon swimming in still water jumps out
of the water with a speed of 6.26 m/s at an angle of 45°, sails
through the air a distance L before returning to the water, and
then swims a distance L underwater at a speed of 3.58 m/s
before beginning another porpoising maneuver. Determine
the average speed of the fish.


Expert Answer

Step 1

Given information:

Velocity of the fish coming out of the water (u) = 6.26 m/s

Angle at which it comes out (θ) = 450

Distance it travels in the air = L = distance it travels under water

The speed at which it travels under water against the stream (v) = 3.58 m/s

Step 2

Distance travelled in air (L) is given by ...


Image Transcriptionclose

6.262 sin2(45) u?sin20 = 3.99 = 4 m 9.81 Time taken to travel this distance is given by: 2usine 2(6.26)sin45 T1 0.902 s 9.81 Time taken to travel distance "L" under the water is given by: 4 : 1.11 s T2 3.58


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