Chlorine gas can be produced from the reaction of potassium permanganate and hydrochloric acid as shown in the following equation: 2KMnO4(s) + 16HCl(aq) → 8H₂0)+2KCl(aq) + 2MnCl2(aq) + 5C12(g) If 4.16 g of KMnO₂ (molar mass = 158.03 g/mol) is reacted with 30.0 mL of 12.01 M HCI at 35 °C and 1.03 atm, how many liters of Cl₂ can be produced? Select one: O a. 1.62 L O b. 2.54 L O c. 2.28 L O d. 1.93 L

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Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.24PAE: 4.24 Ammonia gas can be prepared by the reaction CaO(s)+2NH4Cl(s)2NH3(g)+H2O(g)+CaCl2(s) If 112 g of...
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Chlorine gas can be produced from the reaction of potassium permanganate and hydrochloric acid as shown in the following equation:
2KMnO4(s) + 16HCl(aq) → 8H₂0)+2KCl(aq) + 2MnCl2(aq) + 5C12(g)
If 4.16 g of KMnO₂ (molar mass = 158.03 g/mol) is reacted with 30.0 mL of 12.01 M HCI at 35 °C and 1.03 atm, how many liters of
Cl₂ can be produced?
Select one:
O a.
1.62 L
O b. 2.54 L
O c. 2.28 L
O d. 1.93 L
Transcribed Image Text:Chlorine gas can be produced from the reaction of potassium permanganate and hydrochloric acid as shown in the following equation: 2KMnO4(s) + 16HCl(aq) → 8H₂0)+2KCl(aq) + 2MnCl2(aq) + 5C12(g) If 4.16 g of KMnO₂ (molar mass = 158.03 g/mol) is reacted with 30.0 mL of 12.01 M HCI at 35 °C and 1.03 atm, how many liters of Cl₂ can be produced? Select one: O a. 1.62 L O b. 2.54 L O c. 2.28 L O d. 1.93 L
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