Question
Asked Sep 13, 2019
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Chlorine is used to disinfect swimming pools. The accepted concentration for this purpose is 1 ppm chlorine or 1 g of chlorine per million g of water. Calculate the volume of a chlorine solution (in milliliters) a homeowner should add to her swimming pool to achieve 1.00 ppm chlorine if the solution contains 6.00 perce chlorine by mass and there are 6.63 ×104 gallons of water in the pool. (1 gallon = 3.79 L; density of liquids = 1.00 g/mL.)

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Expert Answer

Step 1

The values are given as follows:

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volume of water in the swimming pool =6.63 x104 gallons 1 gallons 3.79L density of liquids 1.00 g/m % of chlorine by mass in the soluti on 6%

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Step 2

The concentration of chlorine consume is 1 g of Cl in 106 g of water.

Total volume of water in the swimming pool can be calculated as follows:

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6.63x10 gallons 6.63x10 x3.79 L 25.128x10 L 2.5128 x10 L Since 1 L-1000 ml So. 2.5128x10 L-(2.5128x10)(1000) ml 2.512x10 ml

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Step 3

Density of water is 1 g/ml so, mass of water ...

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Since 1g of chlorine 10g of water So 1g of water 10 of chlorine And g of water = (2.512x10) (10)g of chlorine 251.2g of chlorine 2.512x10

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