Choose the allowable Combination of quam tum number for an electrons ? (1) m = 5 1 = 0, me =0. (1) 3=4 1=0 me= 1 A (1²) m=5. I = 5 l=2 (iv) m = 3, (v) m = 3, I = (1) 2=2, 1 = 0 " m₁ = = 1/2 + 12 + 1/₂ ms= -2, me = 1 ms = + 1/₂ /2 + me=0 ms=1 21 = 0 , me = 1 ms=-1 1 ms= 1
Choose the allowable Combination of quam tum number for an electrons ? (1) m = 5 1 = 0, me =0. (1) 3=4 1=0 me= 1 A (1²) m=5. I = 5 l=2 (iv) m = 3, (v) m = 3, I = (1) 2=2, 1 = 0 " m₁ = = 1/2 + 12 + 1/₂ ms= -2, me = 1 ms = + 1/₂ /2 + me=0 ms=1 21 = 0 , me = 1 ms=-1 1 ms= 1
Chemistry: The Molecular Science
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ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter5: Electron Configurations And The Periodic Table
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Transcribed Image Text:Choose the allowable Combination of
quam tum number for an
electrons ?
ms: - 1
l=0, me -0.
0,
f = 0, me =
(1) m = 5₁ l =
(IP) 3=4
(v) m = 3,
(vi) n=2,
(11i) m = 5 ~ 1=5
(iv) m = 3,
2nd =
0
I = 2, me = 1
-2,m1 =
1
=
e-
1=0
+
1
me=0
Ms = - 1/1/2
ms=
2
m₂ = + 1₂2
+ ½/₂
ms=
m₁ = + 1/₂2
1 ms = 1
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