For the cross section shown below, y 1 4a 1 8a I 8a 4a -10a 28a 8a 6a Dimensions in millimeters a) calculate the first moment of the area about x and y axes (Qx and Qy) b) locate the coordinates of the centroid. ४
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a = 11.66 mm
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- Determine the deflection at point D. A. 164400/EIB. 164600/EIC. 144600/EID. 146400/EIQ4 length in m=388The beam cross sections shown are symmetric about the x and y axes. Determine the area moments of inertia Ix and Iy and the radii of gyration kx and ky. (Ans: Ix=4.64x107 mm4, Iy=4.58x106 mm4, kx=105 mm, ky=33.1 mm) ( Hand written and clean writing )
- Use Virtual Work Method to calculate the rotation at C for the frame shown in the accompanying illustration. Use EI=50.0×103kN∙m2Gate ACB is in a shape of a sector of a circle whose radius is 6m as shown. Determine the following: a) Horizontal component FH is Blank 1 KN b) Vertical component Fv is Blank 2 KN c) Distance of FH from point "C" is Blank 3 m c) Distance of Fv from point "C" is Blank 4 mUpvote will be given. Solve im 2 decimal places.
- Find the position of the centroid as well as the moment of inertia with respect to a horizontal axis passing through the centroid in two different ways: (a) By adding the areas. (b) Considering the absence of area as a negative area Answer: 1503.79cm4Calculate the distance (y) to the centroid C of the channel section shown in the figure if a=150mm, b=25mm, c=50mm And also calculate the moment of inertia (Ixc) with respect to an axis that passes through the centroid C and is parallel to the x-axis.12 - Find the center of gravity M of the three dimensional homogeneous wire ABCD by using the coordinate set (x, y, z) in the figure. The dimensions of the wire are a = 15 cm, b = 27 cm. Which of the following is the coordinate of the homogeneous wire in the z axis correct?A) 13.71B) 12.03C) 11.43D) 9,08E) 10.33
- Ƭ allow (MPa)=15 T1 (Nm)=35 T2 (Nm)=50 T3 (Nm)=60 T4 (Nm)= 70 T5 (Nm)=80The following table shows the deflection angles from vertex A to G (deflection angles, the angle formed by the deviation between the direction of the initial line and the direction of the next line. Angle of deviation or deflection, towards right (D) or left (I).It is a closed traverse, the azimuth G-A is 120 ° 00 ', calculate the directions of each of the directions in bearing and azimuth, draw the directions.I cannot understand these For point of contraflexural, 40090300=200×x90300 x=2 m θA=0 (fixed support) θDA=θD-θA=θD=Area of MEI Dia between A and D = 19030012×600×3+600×4+12×300×3-12×200×2 =355090300 θD=0.03931 radianθD= 2.252° Deflection at point D ∆D=31-CosθD ∆D=2.3176×10-3 mm Deflection at point D is 2.3176×10-3 mm