class ThreadB extends { Il extends which class int b1, b2; public ThreadB { I/ arguments b1 = start; b2 = end; /l set the name of thread } public void run() { while( b1 <= b2) { System.out.printin(Thread.currentThread().getName()+" "+ b1); try { Il put thread to sleep for 3000 ms b1 += 2; } catch( ex) { I/ which exception to catch System.out.printin("error :"+ex.getMessage()); } } } } public class MianThreadA { public static void main( String || args ) { Il Create a thread thrdB1 of the class using values 100, 200, "Even" II Create a thread thrdB2 of the class using values 101, 200, “Odd" System.out.printIn("Thread output\n"); Il Start the two threads }
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- whats wrong in code #include int counter; static void * thread_func(void * _tn) { int i; for (i = 0; i < 100; i++) counter++; return NULL; } int main( ) { int i, N = 5; pthread_t t[N]; for (i = 0; i < N; i++) pthread_create(&t[i], NULL,thread_func, NULL); for (i = 0; i < N; i++) pthread_join(t[i], NULL); printf("%d\n", counter); return 0; }Write program for the following Create a child thread class for sorting an array of 10000 size string values Create a child class for calculating factorial of 50 Create a child thread class for calculating base b to the power p Create a single object of each thread in the main thread, and stop the execution of main thread until the termination of all child threads using join methodAssignment 5.py: #Assignment 5 import Queueimport threadingimport timeimport random THREADS = 200 class addingThread (threading.Thread):def __init__(self, l):threading.Thread.__init__(self)self.threadID = 3self.name = "addingThread"self.l = lself.iteration = 0 def run(self):#delay start by a random time between 0 and 0.1 secsleep_time= random.randint(1,1000)/10000.0time.sleep(sleep_time)while self.iteration < len(self.l):#remove the comment for Question 1.3#lock.acquire()self.l[self.iteration] = self.l[self.iteration] +1#remove the comment for Question 1.3#lock.release()self.iteration= self.iteration + 1#remove the comment for Question 1.3 #lock = threading.Lock()workList = range(1,101)threads = [] # Create new threadsthread_num=0while thread_num < THREADS:thread = addingThread(workList)threads.append(thread)thread_num = thread_num +1 # Start threadsfor t in threads:t.start() # Wait for all created threads to finishfor t in threads:t.join() #print final listprint "Final list:…
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- If you declare an array double[] list = {3.4, 2.0, 3.5, 5.5}, list[1] is ________. When a thread extends the Thread class, it must implement the sleep( ) methodIn Python code: Modify this threading example to use, exclusively, multiprocessing, instead of threading. import threadingimport time class BankAccount(): def __init__(self, name, balance): self.name = name self.balance = balance def __str__(self): return self.name # These accounts are our shared resourcesaccount1 = BankAccount("account1", 100)account2 = BankAccount("account2", 0) class BankTransferThread(threading.Thread): def __init__(self, sender, receiver, amount): threading.Thread.__init__(self) self.sender = sender self.receiver = receiver self.amount = amount def run(self): sender_initial_balance = self.sender.balance sender_initial_balance -= self.amount # Inserting delay to allow switch between threads time.sleep(0.001) self.sender.balance = sender_initial_balance receiver_initial_balance = self.receiver.balance receiver_initial_balance += self.amount # Inserting delay to allow switch between threads…In Java multithreading environment, one thread can send an interrupt to another by calling theinterrupt() method on the Thread object for the target thread (i.e., the thread to beinterrupted). To handle interrupts in a target thread, Java allows two approaches. One is performedby writing an exception handler for InterruptedException (only applicable if the targetthread is invoking methods which throw that exception such as sleep). The other approach isperformed by periodically checking the interrupt status flag Thread.interrupted andperforming the handling routine when that flag is set to true.Write a Java program that illustrates the use of the two approaches described above. Your programshould start by creating two threads, each thread should use different interrupt handling approach.Then, the program needs to send interrupts to each one of the created threads such that a threadneeds to return (i.e., stop execution) after receiving an interrupt from the main thread. Make sureto…
- Write a program that launches 1,000 threads. Each threadadds 1 to a variable sum that initially is 0. You need to pass sum by reference toeach thread. In order to pass it by reference, define an Integer wrapper object tohold sum. Run the program with and without synchronization to see its effect.Java: In this scenario, one thread is waiting for another thread to finish transfer and vice versa. They are stuck with each other, and the program cannot continue. Thus, deadlock occurs. To avoid deadlock it is necessary to lock accounts in the same order. To fix the program we’ll give each account a unique number so that we can lock accounts in the same order when transferring the money. // // DeadlockAccounts.java // public class DeadlockAccounts { public static void main(String[] args) throws InterruptedException { class Account { int balance = 100; public Account(int balance) { this.balance = balance; } public synchronized void deposit(int amount) { balance += amount; } public synchronized boolean withdraw(int amount) { if (balance >= amount) { balance -= amount; return true; } return false; } public synchronized boolean transfer(Account destination, int amount) { if (balance >= amount) { balance -= amount; synchronized(destination) {…Implement the producer consumer problem (also known as bounded buffer problem) in java. create two threads i.e. the producer thread and the consumer thread. Create a shared buffer object using a LinkedList or Queue. The producer adds data to the buffer and the consumer removes data from the buffer. The producer cannot add data if the buffer is full and the consumer cannot remove data from the buffer if it is empty. Make sure there are no race conditions and deadlocks.