Coefficients Linear in the Two variables: Solve the equation (x + 2y – 4) dx - (2x + y - 5) dy = 0 O (x - y - 1) = c (x + y – 3) In (x – y - 1) = c (x + y – 3)
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- (With Solution) Find the particular solution of (x + y − 3)dx + (x + y + 5) dy = 0 when x = 1, y = 0. a. (x + y + 5)² = 16x + 20 b. (x + y - 3)² = 16x - 20 c. (x + y 3)³ = 16x + 20 d. (x + y + 5)² = 16x - 20Test for its exactness to obtain the general solution or particular solution if possible. (y2 −2xy+6x)dx−(x2 −2xy+ 2)dy= 0Seperate the variables and solve the equation (dy/dx)=-e^(x-y). Use the initial condition x=0; y=0 to find the arbitrary constant C.