Question
Asked Oct 21, 2019
Combustion analysis of 63.8 mg of a C, H andO containing compound produced
145.0 mg of CO2 and 59.38 mg of H2O. What is the empirical formula for the
compound?
OC3H7O
OC6HO3
CHO
OC5H20
OCaH6o
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Combustion analysis of 63.8 mg of a C, H andO containing compound produced 145.0 mg of CO2 and 59.38 mg of H2O. What is the empirical formula for the compound? OC3H7O OC6HO3 CHO OC5H20 OCaH6o

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Expert Answer

Step 1

The amount of Carbon, Oxygen and Hydrogen in...

44.01 g CO2 contains 12.01 g C.
12.01 g C
Mass of C in 0.145 g CO2
0.145 g CO2 x-
44.01 g CO2
0.0396 g C
59.38 g H2O contains 2.02 g H
2.02 g H
Mass of H in 0.05938 g H2O = 0.05938 g H2Ox
18.02 g H2O
=6.66x103 g H
(0.0638 g)-(0.0396 g+6.66x103
Mass of O
gg
= 0.01754 g
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44.01 g CO2 contains 12.01 g C. 12.01 g C Mass of C in 0.145 g CO2 0.145 g CO2 x- 44.01 g CO2 0.0396 g C 59.38 g H2O contains 2.02 g H 2.02 g H Mass of H in 0.05938 g H2O = 0.05938 g H2Ox 18.02 g H2O =6.66x103 g H (0.0638 g)-(0.0396 g+6.66x103 Mass of O gg = 0.01754 g

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