Combustion analysis of an unknown compound containing only carbon and hydrogen produced 0.1422 g of CO2 and 0.0725 g of H2O. What is the empirical formula of the compound?

Q: acrylic acid used in the manufacture of acrylic plastics has the composition 50.%C 5.6%H and 44.4%O…

A:

Q: A compound is composed of only carbon and hydrogen contains 85.7% C and 14.3% H by mass. What is the…

A: Given: The percentage of carbon in the compound = 85.7 % The percentage of hydrogen in the compound…

Q: What is the empirical formula and empirical formula mass for C7H14?

A: Given,      Molecular Formula: C7H14

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 13.51 g H2O. Calculate the empirical…

A:

Q: Combustion of a hydrocarbon in a limited supply of air produces CO in addition to CO, and H,O. When…

A:

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 4.83 g H2O. What is the empirical…

A: Given : Mass of CO2 produced = 33.01 g Mass of H2O produced = 4.83 g And the compound is…

Q: When 5.942 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 19.34 grams…

A: When organic compounds undergo combustion, they produce carbon dioxide and water. Chemical reactions…

Q: What is the empirical formula of a compound composed of 21.7 g21.7 g of potassium (KK) and 4.44…

A: Given:Mass of potassium = 21.7 gMass of oxygen = 4.44 g.

Q: What is the empirical formula of a compound that contains 63.25% Xe and 36.66%F by mass?

A: Empirical formula :-  The simplest formula which shows only relative number of different atoms…

Q: A combustion analysis of a 0.4647-g sample of a compound known to contain only carbon, hydrogen, and…

A:

Q: Burning a compound of calcium, carbon, and nitrogen in oxygen in a combustion train generates…

A: Empirical formula of a chemical compound is the simplest whole number ratio of the elements that is…

Q: Combustion analysis of 0.800 grams of an unknown hydrocarbon yields 2.613 g CO2 and 0.778 g H2O.…

A: Combustion refers to the process where a substance burns in the presence of oxygen, giving off heat…

Q: Combustion analysis of 2.400 g of an unknown compound containing carbon, hydrogen, and oxygen…

A: Solution                       We know that Number of moles = (Given Mass) / (Molecular Mass) Mass…

Q: What is the empirical formula for a compound when nitrogen is 1.121 g, hydrogen 0.161 g, carbon is…

A: Empirical formula :-  The chemical formula which shows only the relative number (simplest ratio) of…

Q: A compound contains 47.08% carbon, 6.59% hydrogen, and 46.33% chlorine by mass; the molar mass of…

A:

Q: When 4.673 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 16.05 grams…

A: Given: Mass of compound burned = 4.673 g. Mass of CO2 produced = 16.05 g. Mass of H2O produced =…

Q: White phosphorus, P4, spontaneously bursts into flame in oxygen. If 6.500 g of white phosphorus…

A: Answer: Empirical formula of the compound is the formula that represents the atoms of each type…

Q: What is the empirical formula of a compound composed of 72.36% Fe and 27.64% O by mass?

A: Empirical Formula :-  Empirical formula is the simplest ratio of number of atoms present in a…

Q: A sample of compound X is subjected to elemental analysis and the following percentages by weight…

A: Given   % C = 39.97 %  % H  =  6.73 %  % O  =  53.30  Empirical formula = ?

Q: A 0.3870-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in…

A: Empirical formula of a compound is the simplest positive integer ratio of all the elements present…

Q: Combustion analysis of an unknown compound containing only carbon and hydrogen produced 0.2845 g of…

A:

Q: what is the empirical formula for a compound which contains 0.0134 g of iron, 0.00769 g of sulfur…

A: Mass of iron = 0.0134 g  Number of moles of iron  = 0.0134 g / 55.845 g/mol  = 0.000239 mole Mass of…

Q: A 5.17 g sample of a compound with the formula CxHyOz is combusted and yields 13.0 g CO2 and 2.29 g…

A:

Q: What are the empirical formula and empirical formula mass for C3H9O3?

A: Given molecule is                          C3H9O3

Q: Combustion analysis of 1.00g of a compound containing only C, H, and O yields 2.90g of CO2 and…

A: Since the compound contains only C, H and O. Hence assuming the empirical formula of the compound is…

Q: What is the empirical formula of a compound composed of 35.9 g35.9 g of potassium (KK) and 7.35…

A: The empirical formula of a chemical compound is the simplest positive integer ratio of atoms present…

Q: When 4.464 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 14.01 grams…

A:

Q: 3. A sample of a compound of CI and O reacts with an excess of H2 to give 0.233 g HCI and 0.403 g…

A: Given datas – Mass of HCl formed = 0.233g Mass of H2O formed = 0.403g We can write the expected…

Q: A compound containing only carbon, hydrogen, and oxygen is subjected to elemental analysis. Upon…

A: Given information: Mass of sample = 0.7916 g Mass of carbon dioxide = 1.581 g Mass of water = 0.6474…

Q: Adipic acid is an organic compound composed of 49.31% C, 43.79% O, and the rest hydrogen. If the…

A: To determine the empirical formula and molecular formulas of a compound, we need to follow certain…

Q: A chemist must determine the empirical formula of an ionic compound composed only of iron and…

A:

Q: A 125.6 mg sample of an organic compound containing only carbon, hydrogen, and nitrogen is combusted…

A:

Q: A sample of a compound containing only C and H is burned, producing 0.528 g of CO2 and 0.162 g of…

A: Gievn that Sample has two components = C and H Combustio reaction produces, Mass of CO2 = 0.528 g,…

Q: A compound contains only C, H, and N. Combustion of 35.0 mg of the compound produces 33.5 mg CO2…

A: Given: compound contains only C, H, and N mass of compound = 35 mg mass of CO2 produced = 33.5 mg…

Q: A compound containing only phosphorus and hydrogen was fully combusted and yielded 17.9 g of P4O10…

A: Given statement is : A compound containing only phosphorus and hydrogen was fully combusted and…

Q: Combustion analysis of 63.8 mg of a C, H and O containing compound produced 145.0 mg of CO, and…

A: In above question the empirical formula can be calculate with known of percentage composition of…

Q: Combustion analysis of a 20.00 g sample of a compound containing C, H, N, and O atoms only yields…

A: We have to predict the empirical formula.

Q: Combustion of 31.98 g of a compound containing only carbon, hydrogen, and oxygen produces 62.47 g…

A: Given, Mass of Compound containing only carbon, hydrogen, and oxygen = 31.98 g Amount of  CO2…

Q: What is the empirical formula of a compound that is 54.5% C, 9.2% H, and 36.3% O by mass?

A: Assuming the empirical formula is CxHyOz  hence the ration = C : H : O = x : y : z = mole ration of…

Q: 3) The combustion of 4.000 g of a compound that contains only C, H, N, and Br yields 3.826 g of CO2…

A:

Q: A combustion reaction of 37.6 g of a compound (containing only C, H, and O) yields 106 g CO2 and…

A:

Q: Elemental analysis of an unknown compound shows it to contain 1.314574 g of hydrogen, 13.466853 g of…

A: Molar Mass of Phosphorus = 30.97 g/mol Molar mass of Hydrogen 1.00 g/mol Molar mass of Oxygen = 32…

Q: What is the empirical formula for a compound that contains 0.3686 g of N and 0.6314 g of O?

A: Given, Mass of N = 0.3686g Mass of O = 0.6314g

Q: A 4.78 g sample of a compound with the formula CyH,Oz is combusted and yields 11.9 g CO2 and 5.86 g…

A: Empirical formula of a compound is the formula which is represented by the ratio of minimum number…

Q: Combustion of a 1.031-g sample of a compound containing only carbon, hydrogen, and oxygen produced…

A: Empirical formula is the simplest whole number ratio of the compound. Mass of sample = 1.031g Mass…

Q: A compound is found to consist of 43.64% P and 56.36% O.The molar mass for the compound is 283.88…

A: Element  % of element No. of moles  Simple Ratio P  43.64 43.64 / 31  = 1.407 (1.407)/ (1.407) = 1…

Q: Combustion analysis of a hydrocarbon produces 33.01 g CO2 and 13.51 g H2O. Calculate the empirical…

A: Given: Combustion analysis gives 33.01 g CO2 and 13.51 g H2O.

Q: Combustion analysis of 63.8 mg of a C, H, and O containing compound produced 145.0 mg of CO2 and…

A: Empirical formula is the simplest ratio of the elements present in the exact molecular formula.…

Q: A compound composed of Nitrogen, Carbon, and Hydrogen has the following composition by mass: 60.0 %…

A: Percentage of nitrogen in given compound is,                       Moles of Carbon present in 60g…

Q: What is the empirical formula of a compound that contains 29% Na, 41% S, and 30% O by mass?

A: Emperical formula is the simplest formula of the molecule in which atoms are present in simple…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.