Compare and contrast the amount of caffeine obtained from the single vs multipleextractions with Red Bull and Coca-Cola beverages. Explain why this has occured. Single Extractions: TEST SOLUTION NAME ABSORBANCE READING [CAFFEINE]mg/100ml 5ml Red Bull 2.412 57.9mg/100ml 5ml Coca-Cola 0.716 16.2mg/100ml Multiple Extractions: TEST SOLUTION NAME ABSORBANCE READING [CAFFEINE]mg/100ml 10ml Red Bull 3.253 78.453mg/100ml 10ml Coca-Cola 0.785 17.844mg/100ml

Compare and contrast the amount of caffeine obtained from the single vs multipleextractions with Red Bull and Coca-Cola beverages. Explain why this has occured. Single Extractions: TEST SOLUTION NAME ABSORBANCE READING [CAFFEINE]mg/100ml 5ml Red Bull 2.412 57.9mg/100ml 5ml Coca-Cola 0.716 16.2mg/100ml Multiple Extractions: TEST SOLUTION NAME ABSORBANCE READING [CAFFEINE]mg/100ml 10ml Red Bull 3.253 78.453mg/100ml 10ml Coca-Cola 0.785 17.844mg/100ml

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter31: Introduction To Analytical Separations

Section: Chapter Questions

Problem 31.5QAP

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Similar questions

Compare and contrast the amount of caffeine you obtained from the single vs multipleextractions with Red Bull and Coca-Cola beverages. Explain why this has occured. Single Extractions: TEST SOLUTION NAME ABSORBANCE READING [CAFFEINE]mg/100ml 5ml Red Bull 2.412 57.9mg/100ml 5ml Coca-Cola 0.716 16.2mg/100ml Multiple Extractions: TEST SOLUTION NAME ABSORBANCE READING [CAFFEINE]mg/100ml 10ml Red Bull 3.253 78.453 10ml Coca-Cola 0.785 17.844
A 50.0 mL juice extract is colorimetrically assayed using Nelson’s test. One milliliter (1.00 mL) of the solution and the standard glucose solution (concentration: 1mg/mL) were treated with freshly prepared Nelson’s reagent and arsenomolybdate reagent and then diluted to 10.0 mL separately in properly labeled test tubes. Absorbance at 480 nm for the standard is 1.702 and for the sample, 0.926. A. What is the principle behind the assay? B. Calculate the concentration of the reducing sugar in the 50.0 mL sample in mg/mL. Apply Beer-Lambert’s law.
A 50.0 mL juice extract is colorimetrically assayed using Nelson’s test. One milliliter (1.00 mL) of the solution and the standard glucose solution (concentration: 1mg/mL) were treated with freshly prepared Nelson’s reagent and arsenomolybdate reagent and then diluted to 10.0 mL separately in properly labeled test tubes. Absorbance at 480 nm for the standard is 1.702 and for the sample, 0.926. A. What is the principle behind the assay? B. Calculate the concentration of the reducing sugar in the 50.0 mL sample in mg/mL. Apply Beer-Lambert’s law: A=bc
A 50.0 mL juice extract is colorimetrically assayed using Nelson’s test. One milliliter (1.00 mL) of the solution and the standard glucose solution (concentration: 1mg/mL) were treated with freshly prepared Nelson’s reagent and arsenomolybdate reagent and then diluted to 10.0 mL separately in properly labeled test tubes. Absorbance at 480 nm for the standard is 1.702 and for the sample, 0.926. A. What is the principle behind the assay?
1. Describe the different types of analytes which can be analyzed using the different methods of optical analyses. 2. Why is it that absorbance readings be done at lambda max?
You have carried out an experiment using the spectrophotometry concept. A solutioncontaining compound X is mixed with reagent 1 and then reagent 2. This mixture produces ablue colour whose absorbance (A) could be read at 550 nm. The results are shown below If the standard solution (compound X) used have a concentration of 1 mM: 5. What is the reason for using test tube no. 1 in the table above? Can it be replaced withdistilled water?
A 0.1 g amine-containing compound is dissolved in water then diluted to 100 mL. To get the concentration of amine in this compound, you subject it to spectroscopic analysis. So, you get 1 mL of the previously diluted sample then dilute it again to 250 mL for measurement. Then, you fill 3/4 of a 1-cm cuvette with this diluted sample then you run an analysis using an AAS. The recorded absorbance is 0.545 at 410 nm. Solve for the molecular weight of the compound. The molar absorptivity is 1.23 x 104 cm-1 mol-1 L.
A 50.0 mL juice extract is colorimetrically assayed using Nelson’s test. One milliliter (1.00 mL) of the solution and the standard glucose solution (concentration: 1mg/mL) were treated with freshly prepared Nelson’s reagent and arsenomolybdate reagent and then diluted to 10.0 mL separately in properly labeled test tubes. Absorbance at 480 nm for the standard is 1.702 and for the sample, 0.926. Calculate the concentration of the reducing sugar in the 50.0 mL sample in mg/mL. Apply Beer-Lambert’s law: A=bc.
Based on the data, calculate the concentration of analyte in the ORIGINAL sample in ppm. Report to 1 decimal place Sample: A 10.00 mL aliquot of the unknown was placed in a 100.0 mL volumetric flask and made up to the mark will distilled water. The absorbance of this solution is 0.185. Sample + Spike: A 10.00 mL aliquot of the unknown and a 13.00 mL aliquot of the 46.00 ppm stock were both placed in the same 100.0 mL volumetric flask and diluted to the mark with water. The absorbance of this solution is 0.326. ( Please type answer note write by hend)
You have a solution with a concentration of 0.80 mM, and you put it in a cuvette with a 1.0cm pathlength. You read an absorbance of 0.400. What is the extinction coefficient of your analyte? Question 4 options: 0.50 mmole/L/cm 0.50 mmol/L (cm)-1 0.50 L/mmole/cm 0.50 mM cm
Compound X was dissolved in a 5-mL volumetric flask. A 1.00-mL aliquot of the compound was placed in a 10-mL volumetric flask and diluted to the mark. The solution was read in a UV-Vis spectrophotometer and an absorbance of 0.427 in a 1.000-cm cuvette was observed at 340 nm. Solve the following question. Data for Compound X:Molecular mass = 292.16 g/molMolar absorptivity (ɛ) at 340 nm= 6130 M -1 cm -1 a. Calculate the concentration of compound X in the cuvette. b. How many milligrams of compound X were used to make the 5-mL solution?
Compound X was dissolved in a 5-mL volumetric flask. A 1.00-mL aliquot of the compound was placed in a 10-mL volumetric flask and diluted to the mark. The solution was read in a UV-Vis spectrophotometer and an absorbance of 0.427 in a 1.000-cm cuvette was observed at 340 nm. Solve the following question. Data for Compound X:Molecular mass = 292.16 g/molMolar absorptivity (ɛ) at 340 nm= 6130 M -1 cm -1 1. What was the concentration of compound X in the 5-mL flask?