Complete the do-while loop to output from 0 to the value of countLimit using printVal. Assume the user will only input a positive number. For example, if countLimit is 5 the output will be 0 1 2 3 4 5 #include 3 int main(void) { int countLimit; int printval; 5 6. // Get user input scanf("Xd", &countlimit); printval - e; do ( printf("Xd ", printVal); printval - printVal + 1; } while (/ Your solution goes here */ ); printf("\n"); 10 11 12 13 14 15 16 17 return e; 18

Complete the do-while loop to output from 0 to the value of countLimit using printVal. Assume the user will only input a positive number. For example, if countLimit is 5 the output will be 0 1 2 3 4 5 #include 3 int main(void) { int countLimit; int printval; 5 6. // Get user input scanf("Xd", &countlimit); printval - e; do ( printf("Xd ", printVal); printval - printVal + 1; } while (/ Your solution goes here */ ); printf("\n"); 10 11 12 13 14 15 16 17 return e; 18

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less than 100. End each prompt with a newline. Ex: For the user input 123, 395, 25, the expected output is: Enter a number (<100): Enter a number (<100): Enter a number (<100): Your number < 100 is: 25 #include <iostream>using namespace std; int main() {int userInput; /* Your solution goes here */ cout << "Your number < 100 is: " << userInput << endl; return 0;} Please help me with this problem using c++.
Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less than 100. End each prompt with a newline. Ex: For the user input 123, 395, 25, the expected output is:Enter a number (<100): Enter a number (<100): Enter a number (<100): Your number < 100 is: 25 #include <iostream>using namespace std; int main() { int userInput; /* Your solution goes here */ cout << "Your number < 100 is: " << userInput << endl; return 0;}
In Java A while loop reads integers from input. Write an expression that executes the while loop until a positive integer is read from input. Ex: If the input is -20 -43 -25 -22 15, then the output is:User entered -20User entered -43User entered -25User entered -22Loop terminated while () {
What is the output of the following (when embedded in a complete program)? int n = 5; while (--n > 0) { if (n ==2) break; cout<<n<<””; } cout<<”End of Loop.”;
Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less than 100. End each prompt with newline Ex: For the user input 123, 395, 25, the expected output is: Enter a number (<100): Enter a number (<100): Enter a number (<100): Your number < 100 is: 25 import java.util.Scanner; public class NumberPrompt {public static void main (String [] args) {Scanner scnr = new Scanner(System.in);int userInput; /* Your solution goes here */ System.out.println("Your number < 100 is: " + userInput);}}
1. Write a program that asks the user for the price of several items sold until the user answers with an “N”. The program should accumulate the total of all prices entered. After the loop is finished, the program is to compute the sales tax of all items as 7% [0.07]. Finally, the program is to print out the total of the items, the sales tax due, and the total amount due on three separate lines.
The for loop in (a) is converted into the while loop in (b). What is wrong? Correct it. (java language) (a) int sum = 0; for (int i = 0; i < 4; i++) { if (i % 3 == 0) continue; sum += i; } (b) int i = 0, sum = 0; while (i < 4) { if (i % 3 == 0) continue; sum += i; i++; }
What will be the value of x after the following code is executed? int x = 10, y = 20; while (y < 100) { x = x + y; } A) 90 B) 110 C) 210 D) This is an infinite loop.
Write an expression that executes the loop while the user enters a number greater than or equal to 0.Write an expression that executes the loop while the user enters a number greater than or equal to 0. #include <stdio.h> int main(void) { int userNum; scanf("%d", &userNum); while (/* Your solution goes here */) { printf("Body\n"); scanf("%d", &userNum); } printf("Done.\n"); return 0;}
Output integer's digits Given an input positive integer, output each digit on its own line, starting with the rightmost digit. Ex: If the input is 935, the output is: 5 3 9 Hints: Use the mod operator (%) to get the rightmost digit. Mod by 10 to get the rightmost digit. Use a loop that keeps a current dividend (the number being divided). In each iteration, output the rightmost digit, then update the divisor by dividing by 10. End the loop when the divisor is 0. in java
C++ Write a while loop that prints userNum divided by 4 (integer division) until reaching 2 or less. Follow each number by a space. Example output for userNum = 160:40 10 2 Note: These activities may test code with different test values. This activity will perform four tests, with userNum = 160, then with userNum = 8, then with userNum = 0, then with userNum = -1. See "How to Use zyBooks".Also note: If the submitted code has an infinite loop, the system will stop running the code after a few seconds, and report "Program end never reached." The system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() { int userNum; cin >> userNum; /* Your solution goes here */ cout << endl; return 0;} This is what I came up with but it produces no output
Complete the do-while loop to output from 0 to the value of countLimit using printVal. Assume the user will only input a positive number. For example, if countLimit is 5 the expected output will be0 1 2 3 4 5