Complete the following program ArrayMax.java. The function max() should return a new array containing the max value of each corresponding value in two arrays. Below is the code, with the section that needs to be completed. The output should look exactly like what is given below, also
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Complete the following program ArrayMax.java. The function max() should return a new array containing the max value of each corresponding value in two arrays.
Below is the code, with the section that needs to be completed.
The output should look exactly like what is given below, also
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- import java.util.*;class Arraylist{public static void main(String args[]){ArrayList obj = new ArrayList();obj.add("A");obj.add("B");obj.add("C");obj.add(1, "D");System.out.println(obj);}} What will the given code prints on the output screen.java getDup accepts an array and returns an int. If there is any element is duplicated, the method counts how many of those present in the array. Example : getDup(["1","2","aa"',"1"]) returns:2 ("1" is duplicated and there are two "1"s so return is 2) class Main { public static int getDup(String[] r) { } public static void main(String[] args) { Scanner in = new Scanner(System.in); String [] strs = new String[in.nextInt()]; for(int i=0; i < strs.length; i++) { strs[i] = in.next(); } System.out.println(getDup(strs)); } } hint: you will need a nested array the will run on the array we get from the method argument. inside the nested loop you will need to check if the main array element is equal to the currentWrite Java statements to add the integers 1001, 1100, and 1110 to the resulting ArrayList import java.util.*;public class test { public static void main(String[] args) { //Set n =25 int n = 25; //ArrayList of Integer type with size,n=25 ArrayList<Integer> list = new ArrayList<Integer>(n); for(int i = 0;i<n;i++){ //Assign -1 to all the objects of the array list,list list.add(-1); } //Add 1001 to the list list.add(1001); //Add 1100 to the list list.add(1100); //Add 1110 to the list list.add(1110); //Reset the number of elements in the list becomes 28 //Use size() method to get the size of the list. n=list.size(); //for loop to print the list for(int i = 0;i<n;i++){ System.out.print(list.get(i) + " "); } }} 1. Write the Java statement to display the size of the resulting ArrayList from above.
- Return an ArrayList containing the largest and smallest integer inan array. If the array is empty, return the largest andsmallest as 0. languages java please help me thanksin java wirte a method that given an integer array, computes and returns an integer x. the starting value of x is equal to the array length. for every odd element in the array, substract it from x, and for every even element in the array add it to x . Example: Array: [13,2,3,4,5] Result: x=5-13+2-3+4-5 x= -10Create Test Suit for all test cases public class Arraymethod { public static void main(String[] args) { int [] array = {2,5,10,8,9,3}; System.out.println("Sum of array elements is:"+sum(array)); System.out.println("Average of array elements is:"+avg(array)); System.out.println("Maximum element of array is:"+max(array)); System.out.println("Minimum element of array is:"+min(array)); } //method for calculating sum of array elements public static int sum(int[] array) { int sum = 0; for(int i=0; i array[i]) { min = array[i]; } } return min; } } Create Test Suit for all test cases
- Using this code in Java: public class Main { public static void main(String[] args) {// change the dimension to 500, 5000 to repeat for big array sizefinal int dimension = 50;System.out.println("Array dimension: "+ dimension);//aint[] array = new int[dimension]; //b for (int ink = 0; ink < dimension; ink++) array[ink] = ink; //c String stringObject = new String(); // d record time long startTime = System.currentTimeMillis(); for (int ink = 0; ink < dimension; ink++) stringObject += array[ink]; long endTime = System.currentTimeMillis(); //e System.out.println("Time to append using string object: " + (endTime - startTime) + " ms."); //f StringBuilder builder = new StringBuilder(); startTime = System.currentTimeMillis(); for (int ink = 0; ink < dimension; ink++) builder.append(array[ink]); endTime = System.currentTimeMillis(); //e System.out.println("Time to append using string builder object: " + (endTime - startTime) + " ms."); } }In JAVA Please. Complete the calcAverage() method that has an integer array parameter and returns the average value of the elements in the array as a double. Ex: If the input array is: 1 2 3 4 5 then the returned average will be: 3.0 import java.util.*;public class Numbers {// calcAverage() takes in an int array and returns the average value of elements in the array as a double.public double calcAverage(int[] nums) {/* Type your code here. */ }public static void main(String[] args) {Numbers numObject = new Numbers();int [] nums = {1,2,3,4,5};System.out.println(numObject.calcAverage(nums)); }}Methods Details: public static java.lang.StringBuffer[] getArrayStringsLongerThan(java.lang.StringBuffer[] array, int length) Returns a StringBuffer array with COPIES of StringBuffer objects in the array parameter that have a length greater than the length parameter. If no strings are found an empty array will be returned. Parameters: array - length - Returns: Throws:java.lang.IllegalArgumentException - When a null array parameter is provided
- Array lists are objects that, like arrays, provide you the ability to store items sequentially and recall items by index. Working with array lists involves invoking ArrayList methods, so we will need to develop some basic skills. Let’s start with the code below: import java.util.ArrayList;public class ArrayListRunner{ public static void main(String[] args) { ArrayList<String> names = new ArrayList<String>(); System.out.println(names); }} The main method imports java.util.ArrayList and creates an ArrayList that can hold strings. It also prints out the ArrayList and, when it does, we see that the list is empty: [ ].Complete the following tasks by adding code to this skeleton program. If you are asked to print a value, provide a suitable label to identify it when it is printed.a) Invoke add() to enter the following names in sequence: Alice, Bob, Connie, David, Edward, Fran, Gomez, Harry. Print the ArrayList again.b) Use get() to retrieve and print the first…public class ReplaceEvenWithZero { public static void main(String[] args) { int[]a = new int[]{14, 2, 19, 3, 15, 22, 18, 7, 44, 39, 51, 78} ; // Print array a for (int i = 0; i < a.length; i++) { System.out.print(a[i] + " "); } System.out.println(); // Replace the even elements. replaceEven(a); // Print array a again to see new elements. for (int i = 0; i < a.length; i++) { System.out.print(a[i] + " "); } System.out.println(); } /** Replace the even elements in the given array with 0 @param arr the array to use for the replacements */ public static void replaceEven(int[] arr) { //-----------Start below here. To do: approximate lines of code = 2 // Write a for loop to go through each element, determine if it is even //If so, replace with 0. Hint: use the modulus operator % to determine if an…Please help me fix this code Make it run out like the picture import java.util.ArrayList; import java.util.Random; import java.util.Scanner; public class FrogListApp { public static void main(String[] args) { final int MIN_WEIGHT = 1; final int MAX_WEIGHT = 25; // Step 3: Create an array list to store Frog objects ArrayList frogsList = new ArrayList<>(); // Step 4: Create a Scanner object Scanner scanner = new Scanner(System.in); // Step 5: Read an integer as the number of frogs // using prompt "Enter the number of frogs: " System.out.print("Enter the number of frogs: "); int numberOfFrogs = scanner.nextInt(); // Step 6: Read an integer as the random generator seed // using prompt…