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- PYYTHON!!! Write a function str_replace that takes three strings, str1, str2 and str3; and replaces the first occurence (if any) of str2 in str1 with str3, and returns the newly formed string. For example, str_replace("Nuclear Energy Engineering", "Nuclear Energy", "Mechanical") returns "Mechanical Engineering" """6.Please_Implement regular expression matching with support for '.' and '*'. '.' Matches any single character.'*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be:bool is_match(const char *s, const char *p) Some examples:is_match("aa","a") → falseis_match("aa","aa") → trueis_match("aaa","aa") → falseis_match("aa", "a*") → trueis_match("aa", ".*") → trueis_match("ab", ".*") → trueis_match("aab", "c*a*b") → true""" def is_match(str_a, str_b): """Finds if `str_a` matches `str_b` Keyword arguments: str_a -- string str_b -- string. """.Write a function findLetter based on the following rules: It takes a string named str and a character named ch as parameter, returns the index of the first occurrence of the character ch if the str string contains the character ch; If the relevant character is not found in the string, write a function that returns -1. Call the function inside the main function and test it. You should use the prototype given below: int findLetter (char str [], char ch)
- String Manipulation In this question, you will be implementing the following functions int findChar(char * str, char c); Searches for the character c in the string str and returns the index of the character in the string. If the character does not exist, returns -1 int replaceChar(char * str, char c1, char c2); Searches for the character c1 in the string str and if found, replace it with c2.The function returns the number of replacements it has performed. If the character does not exist, returns 0. int removeChar(char * str1, char * str2, char c); Creates a copy of str1 into str2 except for the character c that should be replaced with ‘*’ For example, if str1=”Hello World” and c=’l’ then the function should make str2=”He**o Wor*d” int isPalindrome(char * str) Checks to see if a string is Palindrome(reversible). If it is, returns 1, otherwise returns 0. A palindrome string reads similarly from left to right and from right to left like madam, level, radar, etc. int reverseString(char…Create a function called reverse() that has a string parameter. The function reverses the characters of the string locally. ( in C language)Write a function findLetter based on the following rules: It takes a string named str and a character named ch as parameter, returns the index of the first occurrence of the character ch if the str string contains the character ch; If the relevant character is not found in the string, write a function that returns -1. Call the function inside the main function and test it. You should use the prototype given below:
- In C++Take the following code but -for the first option, change it so that instead of the middle element, its the first element -for the third option, change it so that instead of the middle element its the first element #include<iostream>#include<cstdlib>#include<ctime>using namespace std;// this funtion is used to partition the arry based on given pivot//this funtion also takes an string opt(it indicates pivot type) so if type is pivot type is middle element then it selects middle element as pivot//and if pivot type is median element then it selects median element as pivot int Partition(int a[], int low, int high, string opt){ int pivot, ind = low, i, swp; //for type-1 anf type-3 sort we use the middle element as pivot if (opt == "Type1 sort" || opt == "Type3 sort") { pivot = (high + low) / 2; } //for type-2 anf type-4 sort we use the median element as pivot else if (opt == "Type2 sort" || opt == "Type4 sort") { pivot = (high +…(C++) 9. True/False: the strcpy() function will make sure there is enough memory allocated in the destination string before copying C-strings 10. True/False: when creating a string object, you must dynamically allocate enough bytes to hold the string 11. Consider the following statement, assuming goAgain is a valid char. Rewrite it using toupper() or tolower() if (goAgain == 'y' || goAgain == 'Y') 12. Write a C++ function which accepts a pointer to a C-string as its argument. It should return the number of words in the C-string. For example, for the C-string “The Giants won the pennant!” your function should return 5. You may assume the parameter passed is a pointer to a valid, null-terminated C-string with no newlines or tabs, exactly one space separates each word, and there is at least one word. int wordCounter(char* str)#include <iostream>#include <string>#include <climits>using namespace std; class BalancedTernary {protected:// Store the value as a reversed string of +, 0 and - charactersstring value; // Helper function to change a balanced ternary character to an integerint charToInt(char c) const {if (c == '0')return 0;return 44 - c;} // Helper function to negate a string of ternary charactersstring negate(string s) const {for (int i = 0; i < s.length(); ++i) {if (s[i] == '+')s[i] = '-';else if (s[i] == '-')s[i] = '+';}return s;} public:// Default constructorBalancedTernary() {value = "0";} // Construct from a stringBalancedTernary(string s) {value = string(s.rbegin(), s.rend());} // Construct from an integerBalancedTernary(long long n) {if (n == 0) {value = "0";return;} bool neg = n < 0;if (neg)n = -n; value = "";while (n != 0) {int r = n % 3;if (r == 0)value += "0";else if (r == 1)value += "+";else {value += "-";++n;} n /= 3;} if (neg)value = negate(value);} // Copy…
- C++ Create a function print_double_spaced(cs) that takes a C string as an argument and prints the characters of that string separated by a space. For example, the string hello world should be printed as h e l l o w o r l dPlease fill the blanks for C. /*getchar VS scanf*/ #include<stdio.h> #define length 70 //Putting all function headers to top __1__ print_scanf(); __2__ print_getchar(); int main() { //print 2 sentences using getchar() for(int i = 0; i < 2; i++) { print_getchar(); } //print 2 sentences using scanf() for(int i = 0; i < 2; i++) { print_scanf(); } return 0; } //Function to print using getchar void print_getchar() { __3__ str[__4__]; //create a string called str with length defined above printf("Enter your sentence for getchar:"); int i = 0; while(1) //run forever,unless there's a break or return { /*save user's input to curChar since we need to check 2 cases: Case 1. if the inputted character is a letter we save curChar to our string (array of char) Case 2. if it's a new line character.…Write a function called substring that uses the leftmatch and rightmatch functions to remove a pattern from the left and right side of a value. It should take three arguments as shown: $ substring /usr/ /usr/spool/uucppublic /uucppublic spool $ substring s. s.main.c .c main $ substring s. s.main.c .o Only left match main.c $ substring x. s.main.c .o No matches s. main.c