Complete the method below that takes the reference of a non-dummy headed singly linear linked list and removes all the nodes containing multiples of 5 from the list. remove_multiple_of_five(hea
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Complete the method below that takes the reference of a non-dummy headed singly
linear linked list and removes all the nodes containing multiples of 5 from the list.
remove_multiple_of_five(head)
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- implement this method: numOccurrencesRec(LNode node, int n, int key) – This method takes as parameters a reference to the head of a linked list, a position specified by n, and a key. It returns the number of occurrences of the key in the linked list beginning at the n-th node. If n = 0, it means you should search in the entire linked list. If n = 1, then you should skip the first node in the list./ This method takes as parameters a reference to the head of a linked list, a // position specified by n, and a key. It returns the number of occurrences // of the key in the linked list beginning at the n-th node. If n = 0, it means // you should search in the entire linked list. If n = 1, then you should skip // the first node in the list. public int numOccurrencesRec(LNode node, int n, int key) { // TODO: implement this method return 0; // replace this statement with your own return } } LNode Below: public class LNode{ // instance variables private int m_info; private LNode m_link; // constructor public LNode(int info) { m_info = info; m_link = null; } // member methods public void setLink(LNode link) { m_link = link; } public LNode getLink() { return m_link; } public int getInfo() { return m_info; } }// This method takes as parameters a reference to the head of a linked list, a // position specified by n, and a key. It returns the number of occurrences // of the key in the linked list beginning at the n-th node. If n = 0, it means // you should search in the entire linked list. If n = 1, then you should skip // the first node in the list. public int numOccurrencesRec(LNode node, int n, int key) { // TODO: implement this method return 0; // replace this statement with your own return }}
- For a Doubly Linked List implement the following method: void deleteAfterHead() //Delete the second node from the list. If the list has only one element, delete the head. Assume you have deleteFromHead() and deleteFromTail() methods.How to get insert method to accept two values? Right now it accepts one, and ignores the other. class Node: """ Represents a node in a linked list """ def __init__(self, data): self.data = data self.next = None class LinkedList: """ A linked list implementation of the List ADT """ def __init__(self): self._head = None def add(self, val): """ Adds a node containing val to the linked list """ self._head = self.rec_add(self._head, val) def rec_add(self, a_node, val): """ Adds a node containing val to the linked list """ if a_node is None: return Node(val) else: a_node.next = self.rec_add(a_node.next, val) return a_node def insert(self, val, pos): """ Adds a node containing val to the linked list """ self._head = self.insert_add(self._head, val, pos) def insert_add(self, a_node, val, pos): """…To calculate the number of nodes in a circularly linked list with a head node that represents a list of positive integers, write a pseudo-code method. The head node stores the amount of nodes as a negative number.
- Write down the insertBefore method which inserts a new element in the list before the node containing the given element.The method takes as parameters a dummy headed doubly linked circular list, the element existing in the list and new element to be added. public void insertBefore (Node head, Object elem, ObjectnewElement){//to do} insertBefore (head, 3, 50).Create a method to filter out duplicate nodes from a linked list.Develop a method for removing nodes with duplicate keys from a linked list.
- Create an algorithm in a linked list that will eliminate all of the nodes that have the same key.Write down the insertBefore method which inserts a new element in the list before thenode containing the given element.The method takes as parameters a dummy headeddoubly linked circular list, the element existing in the list and new element to be added.public void insertBefore (Node head, Object elem, ObjectnewElement){//to do}insertBefore (head, 3, 50)The following method is defined within a linked list class. What does it do? void MyList::doSomething() { Node* p = head; while (p) { cout << p->value << " "; p = p->next; }} Group of answer choices inserts a node into linked list deletes a node from linked list displays contents of linked list destroys the entire linked list