complete the table below. Show your solution with proper units. Planet Average R° (meters) R / T° { (meters)/ Times of Radius of Revolution (seconds) (seconds) } Planet's Orbit (Planet's year') R T (seconds) (meters) Mercury 5.7869 x 10:° 7.605 x 10 Venus 1.081 x 10! 1.941 x 107 Earth 1.4996 x 10" 3.156 x 10" Mars 2.280 x 10" 5.936 x 107 Jupiter 7.783 x 10" 3.743 x 10 Saturn 1.426 x 10 9.296 x 10
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- Use Kepler's Law, which states that the square of the time, T, required for a planet to orbit the Sun varies directly with the cube of the mean distance, a, that the planet is from the Sun.Using Earth's time of 1 year and a mean distance of 93 million miles, the equation relating T (in years) and a (in million miles) is 804375T2=a3.Use that relation equation to determine the time required for a planet with mean distance of 206 million miles to orbit the Sun. Round to 2 decimal places. yearsPlease answer the question and subquestions completely! This is one whole question which has subquestions! According to the official Bartleby guidelines, each question can have up to two subquestions! Thank you! 1) Use Kepler's Law to find the time (in Earth’s years) for Mars to orbit the Sun if the radius of Mars’ orbit is 1.5 times the radius of Earth's orbit. 1.8 2.8 3.4 4.2 A) The mass of Mars is about 1/10 the mass of Earth. Its diameter is about 1/2 the diameter of Earth. What is the gravitational acceleration at the surface of Mars? 9.8 m/s2 2.0 m/s2 3.9 m/s2 4.9 m/s2 none of these B) A 9.0 x 10 3 kg satellite orbits the Earth at the distance of 2.56 x 10 7 m from Earth’s surface. What is its period? 1.1 x 10 4 s 4.1 x 10 4 s 5.7 x 10 4 s 1.5 x 10 5 sNext you will (1) convert your measurement of the semi-major axis from arcseconds to AU, (2) convert your measurement of the period from days to years, and (3) calculate the mass of the planet using Newton's form of Kepler's Third Law. Use Stellarium to find the distance to the planet when Skynet took any of your images, in AU. Answer: 4.322 AU Use this equation to determine a conversion factor from 1 arcsecond to AU at the planet's distance. You will need to convert ? = 1 arcsecond to degrees first. Answer: 2.096e-5 AU (2 x 3.14 x 4.322 x (.000278/360) = 2.096e-5) Next, use this number to convert your measurement of the moon's orbital semi-major axis from arcseconds to AU. A) Calculate a in AU. B) Convert your measurement of the moon's orbital period from days to years. C) By Newton's form of Kepler's third law, calculate the mass of the planet. D) Finally, convert the planet's mass to Earth masses: 1 solar mass = 333,000 Earth masses.
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- Suppose we discovered a planetary body orbiting our Sun at a distance of 15 AU. How long would this world take to complete one orbit around the Sun? please show work Suppose Astronomers noticed a moon around the newly discovered planet in Question 2. By watching this moon, noting its period and distance from the planet, which of the following could they find: the mass of the moon, the mass of the planet, both masses, neither mass. Explain.Please answer the following A) Suppose an object takes 1000 years to orbit the Sun. How many times farther from the Sun is it, when compared with Earth? B) Communications with the spacecraft Alpha using radio waves require 2000 years for the round trip (there and back). This implies that Alpha is how many light years away from Earth?Please answer the question and subquestions entirely. This is one single question. According to the official guideline, I can ask two subquestions! Thank you! 1) A planet Y is moving in circular orbit around the Sun. If its distance from the Sun is four times the average distance of the Earth from the Sun, what is the Y’s period in Earth years? 3 8 16 32 64 a) Two masses are precisely 1 m apart from each other. The gravitational force each exerts on the other is exactly 1 N. If the masses are identical, what is each mass? 1.22 x 105 kg 1.34 x 1010 kg 2.50 x 105 kg 1.58 x 1010 kg b) What is the acceleration due to gravity on the surface of the planet Pluto if its mass is 1.2 x 10 22 kg and radius is 1.14 x 10 6 m? 9.8 m/s2 6.4 m/s2 0.62 m/s2 0.34 m/s2
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