Correct numbers 1 and 3. Show all work/calculations: Complete this prelab assignment (questions 1-3) on these sheets in the spaces provided. Combine thisalong with a scanned copy of your Lab Notebook and upload to CANVAS before the beginning of yourLab Section.*. In Part A of this experiment, you prepare 5 solutions of FESCN2* [one of them is just a blanksolution] according to the reaction below.Fe3+ (aq) + SCN¯ (aq) → FeSCN²+ (aq)We assume that the starting SCN determines the concentration of formed (because Fe3+ is inexcess and SCN" is limiting). Calculate the concentration of FESCN2* that forms for each of thesolution (Beakers 1- 4) and fill out the table below. Show your calculations beneath the table.Beaker0.200 M0.0020 MConcentration ofNumberFe(NO3)3 (mL]KSCN (mL]H20 [mL]FESCN2* (M)15.05.040.00.000225.04.041.00.000165.03.042.00.0001245.02.043.00.000085 (blank)5.00.045.0181Show your work for question 1 here:Total volume of all beakers = 50 mLMSCN x VSCN(FESCN2*] = (SCN'] =values ok but,you ShouldNOT useTotal VolumeBeaker 1:0.002 x 5(FESCN2"] =50= 0.0002 M%3DBeaker 2:0.002 x 4(FESCN²*] =50= 0.00016 MMiVi=M2V2Beaker 3:Show mol ratio0.002 x 3(FESCN2*] =50= 0.00012 MBeaker 4:0.002 x 4(FESCN2"] =50= 0.00008 M2. In Part A, you measure the absorbance of four FeSCN2* solutions and prepare a Beer's Law plot(Absorbance vs. wavelength] similar to the one below.Beer's Law Plot for FeSCN2+0.6y = 2417.5x + 0.0483R? = 0.9990.5E0.40.30.20.10.000050.00010.000150.00020.00025Concentration (M)You will use this plot as a standard curve in Part B to determine the concentration of anunknown. If an unknown FeSCN2* solution gives an absorbance reading of 0.334, use theequation of the best fit line shown above to determine its concentration. Show all work below.Absorbance You will use this plot as a standard curve in Part B to determine the concentration of anunknown. If an unknown FeSCN2* solution gives an absorbance reading of 0.334, use theequation of the best fit line shown above to determine its concentration. Show all work below.y = absorbance = 0.334y = 2417.5x + 0.0483y - 0.0483X =0.334 - 0.04832417.52417.5x = 1.182 x 10-4 MUnknown [FESCN²*] = 1.182 x 10-4 M%3D1823. In Part C, you prepare four solutions (starting concentrations are given blow) in test tubes andyou will measure the Absorbance after the solutions have reached equilibrium. Shown below isan example of just ONE solution, with absorbance data shown as well. Using this data and thestandard curve from question 2 on the previous page, calculate Kf.SHOW ALL WORK BELOW!Starting ConcentrationsTest Tube0.00200 M Fe(NO3)3 [mL] 0.0020 M KSCN [mL]H20 [mL]13.02.05.0Absorbance Data(FESCN²*] atTest TubeAbsorbance at AmaxequilibriumKf10.1182.88 x 10-4 M121Given absorbance: y = 0.118y – 0.0483X =0.118 – 0.04832417.52417.5x = 2.883 x 10'5 M(FESCN2*] = 2.88 x 10$ M(Fe**) =;MFex VFe0.002 x 3= 0.006 MTotal VolumeMSCN X V SCN100.002 x 2[SCN'] == 0.0004 M%3DTotal Volume10ICE Table:Fe3+SCN-FESCN2+0.0060.0004C-X-X+XE0.006 – x0.004 - x[FESCN2*]Kf =[Fe3+][SCN¯]0.118 = 2417.5+ 0.04832417.5x = 0.334 – 0.0483 = 0.0697(0.006 – x)(0.004 – x)0.0697X =2417.5= 2.88 x 10-5 MAt equilibrium,(FESCN2*] = 2.88 x 105 M(Fe3*] = 0.0060 – x = 0.0060 – 2.88 x 105 = 0.0059712(SCN'] = 0.0040 – x = 0.0040 – 2.88 x 10$ = 0.0039712 not Sure whatwent wrong.-.2.88 x 10-5Kf =(0.0059712 x 0.0039712)Kf = 121

Complete this prelab assignment (questions 1-3) on these sheets in the spaces provided. Combine this along with a scanned copy of your Lab Notebook and upload to CANVAS before the beginning of your Lab Section. *. In Part A of this experiment, you prepare 5 solutions of FeSCN2* [one of them is just a blank solution] according to the reaction below. Fe3+ (aq) + SCN- (aq) → FeSCN²+ (aq) We assume that the starting SCN determines the concentration of formed (because Fe3+ is in excess and SCN- is limiting). Calculate the concentration of FeSCN2* that forms for each of the solution (Beakers 1-4) and fill out the table below. Show your calculations beneath the table.

Complete this prelab assignment (questions 1-3) on these sheets in the spaces provided. Combine this along with a scanned copy of your Lab Notebook and upload to CANVAS before the beginning of your Lab Section. . In Part A of this experiment, you prepare 5 solutions of FeSCN2 [one of them is just a blank solution] according to the reaction below. Fe3+ (aq) + SCN- (aq) → FeSCN²+ (aq) We assume that the starting SCN determines the concentration of formed (because Fe3+ is in excess and SCN- is limiting). Calculate the concentration of FeSCN2* that forms for each of the solution (Beakers 1-4) and fill out the table below. Show your calculations beneath the table.

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter3: Chemical Reactions

Section: Chapter Questions

Problem 125QRT: A student set up an experiment for six different trials of the reaction between 1.00-M aqueous...

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