Compute the minimum length of vertical curve to provide stopping sight distance for a design speed of 100 km/h at the intersection of a +1.4% grade with a -0.6% grade.
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- Compute the minimum length of vertical curve to provide 190 m stopping sight distance for a design speed of 100 km/h at the intersection of a +2.6% grade with a -2.4% grade.A vertical curve links between -3% & -8% grades, the allowed speed on the curve is 80 kmph and the elevation of the point of intersection is equal to 2009 Calculate the elevation of the beginning and end points of the curve?A vertical curve is needed to join to tangents; G1=1% and G2=4%. Assuming a level grade (0%) for braking, and the AASHTO recommended values for deceleration and perception-reaction time, calculate the minimum length of curve (ft) needed to satisfy the safety criteria. The design speed is 60 mph.
- Determine the minimum length (Lmin) of a curve above if the slopes are + 3% and -3%, with a design speed of 75mi / hr, state the assumptions used to solve this problem.An equal-tangent sag vertical curve is designed with the PVC at station 109 + 00 and elevation 950 ft, the PVI at station 110 + 77 and elevation 947.34 ft, and the low point at station 110 + 50. Determine the design speed of the curve.An equal-tangent vertical curve is to be constructed between grades of +1%(initial) and -1%(final). The final point of vertical curvature is at station 0+500 and at elevation 100m. Indicate if this vertical curve is safe for a design speed of 70 km/h regarding stopping sight distance.
- A vertical parabolic curve has a sight distance of 130m. The curve has tangent grades of +2.8% and -1.6% if the height at the driver ‘s eye from the pavement is 1.08m and the height of the object is 0.50m A.)Compute the max speed of the car that can pass thru this curve. B.)Compute the length of the vertical curve in meters for every 1% change in grade. C.)Compute the equivalent radius of the vertical curve.A vertical curve was constructed between the grade (+3) and (-1%). Determined the sight distance required for a vehicle moving on this curve. Where the length of this curve equals this sight distance.Compute the ruling minimum radius of horizontal curve for a design speed of 80 kph,f=0.18 and e = 0.078. For ruling minimum radius, increase the design speed by 16 kph.
- . An equal-tangent crest curve connects a +1.0%and a -0.5% grade. The PVC is at station 54 + 24 and the PVI is at station 56 + 92. Is this curve long enough to provide passing sight distance for a 60-mi/h design speed?A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the PC is at station 3 + 65.00 ft, what is the length (ft) of roadway to the first full station on the curve? The first full station occurs at 4+00A vertical curve is to be designed to connect a -4% grade to a +1% grade on a facility with a design speed of 70 mi/h. For economic reasons, a minimum-length curve will be provided. A driver-reaction time of 2.5 seconds may be used in sight distance determinations. The V.P.I. of the curve is at station 5,100 + 22 and has an elevation of 1,285 ft. find the station and elevation of the V.P.C. and V.P.T., the high point of the curve, and at 100-ft intervals along the curve.