Concentration of NaOH = Volume of HCL x The concentration of HCL/Volume Of NaOH Concentration of NaOH = 25.00 cm³ x 0.10 mol dm-/ 24.7cm3 %3D = 0.10 mol/L 2 Titration of sodium hydroxide and vinegar Method 1 Fill a burette with the solution of NaOH(aq) standardized in part 1. 2 Pipette 5.00 cm' of vinegar onto a clean conical flask. Add a few drops of the indicator phenolphthalein solution to the conical flask and stand it on a white tile or white paper. 4 Titrate the NaOH against the vinegar, until the endpoint of the indicator is observed, and record the volume added from the burette. Repeat the titration until values within 0.05 cm³ are obtained. Results Volume NaOH Titration 1 Titration 2 end volume / cm³ ± 0.05 42.4 42.5 start volume / cm³ ± 0.05 titre / cm³ + 0.10 42.4 42.5 average titre / cm³ ± 0.10 = 42.366 Also, record your qualitative data. Analysis Calculate the number of moles of NaOH required to reach equivalence.

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.107QE
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Calculate the number of Moles of NaOH required to reach equivalence. 

5:04
Concentration of NaOH = Volume of HCL x The concentration of
%3D
HCL/Volume Of NaOH
Concentration of NaOH = 25.00 cm³ x 0.10 mol dm/ 24.7cm3³
= 0.10 mol/L
%3D
2
Titration of sodium hydroxide and
vinegar
Method
1
Fill a burette with the solution of NaOH(aq) standardized in
part 1.
2
Pipette 5.00 cm³ of vinegar onto a clean conical flask.
3
Add a few drops of the indicator phenolphthalein solution
to the conical flask and stand it on a white tile or white paper.
4
Titrate the NaOH against the vinegar, until the endpoint of
the indicator is observed, and record the volume added from
the burette.
Repeat the titration until values within 0.05 cm³ are
obtained.
Results
Volume NaOH
Titration 1
Titration 2
end volume / cm³ ± 0.05
42.4
42.5
start volume / cm³ + 0.05
titre / cm³ + 0.10
42.4
42.5
average titre / cm³ ± 0.10 = 42.366
Also, record your qualitative data.
Analysis
Calculate the number of moles of NaOH required to reach
equivalence.
Transcribed Image Text:5:04 Concentration of NaOH = Volume of HCL x The concentration of %3D HCL/Volume Of NaOH Concentration of NaOH = 25.00 cm³ x 0.10 mol dm/ 24.7cm3³ = 0.10 mol/L %3D 2 Titration of sodium hydroxide and vinegar Method 1 Fill a burette with the solution of NaOH(aq) standardized in part 1. 2 Pipette 5.00 cm³ of vinegar onto a clean conical flask. 3 Add a few drops of the indicator phenolphthalein solution to the conical flask and stand it on a white tile or white paper. 4 Titrate the NaOH against the vinegar, until the endpoint of the indicator is observed, and record the volume added from the burette. Repeat the titration until values within 0.05 cm³ are obtained. Results Volume NaOH Titration 1 Titration 2 end volume / cm³ ± 0.05 42.4 42.5 start volume / cm³ + 0.05 titre / cm³ + 0.10 42.4 42.5 average titre / cm³ ± 0.10 = 42.366 Also, record your qualitative data. Analysis Calculate the number of moles of NaOH required to reach equivalence.
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