Confidence in banks: A news poll conducted in 2012 asked a random sample of 1217 adults in the United States how much confidence they had in banks and other financial institutions. A total of 160 adults said that they had a great deal of confidence. An economist claims that greater than 11% of U.S. adults have a great deal of confidence in banks. Can you conclude that the economist's claim is true? Use both a=0.05 and a 0.10 levels of significance and the critical value method with the table.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
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Confidence in banks: A news poll conducted in 2012 asked a random sample of 1217 adults in the
United States how much confidence they had in banks and other financial institutions. A total of 160
adults said that they had a great deal of confidence. An economist claims that greater than 11% of
U.S. adults have a great deal of confidence in banks. Can you conclude that the economist's claim is
true? Use both a=0.05 and a=0.10 levels of significance and the critical value method with the table.
Part 1 of 5
State the appropriate null and alternate hypotheses.
Ho: P = .11
H: P> .11
This hypothesis test is a right-tailed
▼ test.
Part 2 of 5
Find the critical values. Round the answer to three decimal places.
For a- 0.05 , the critical value is 1.645
For a-0.10 , the critical value is 1.282
Part: 2/5
Part 3 of 5
Compute the test statistic. Do not round intermediate calculations. Round the answer to two
decimal places.
Transcribed Image Text:Confidence in banks: A news poll conducted in 2012 asked a random sample of 1217 adults in the United States how much confidence they had in banks and other financial institutions. A total of 160 adults said that they had a great deal of confidence. An economist claims that greater than 11% of U.S. adults have a great deal of confidence in banks. Can you conclude that the economist's claim is true? Use both a=0.05 and a=0.10 levels of significance and the critical value method with the table. Part 1 of 5 State the appropriate null and alternate hypotheses. Ho: P = .11 H: P> .11 This hypothesis test is a right-tailed ▼ test. Part 2 of 5 Find the critical values. Round the answer to three decimal places. For a- 0.05 , the critical value is 1.645 For a-0.10 , the critical value is 1.282 Part: 2/5 Part 3 of 5 Compute the test statistic. Do not round intermediate calculations. Round the answer to two decimal places.
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