confidence interval for the true proportion

Q: Find the 95% confidence interval for the mean difference of the tests, and explain it.

A: Test - 1 (X) Test-2 (Y) (x-xbar) (x-xbar)^2 (y-ybar) (y-ybar)^2 1.2 1.4 -0.31111 0.09679 -0.24444…

Q: When a survey asked subjects whether they would be willing to accept cuts in their standard of…

A: It is given that 362 out of 1,180 subjects respond yes.The sample proportion is 362/1,180 =…

Q: In a survey of 2344 ​adults, 715 say they believe in

A: Given that there are 2344 adults and 715 say they believe in UFOs. Consider the sample proportion,…

Q: We surveyed 53 people in an attempt to determine the proportion of Americans who lease a vehicle. 13…

A: The proportion of sample Americans who lease a vehicle is, Thus, the proportion of sample Americans…

Q: In a random sample of 100 voters in a school district, 40 of them stated they were in favor of the…

A: Solution: Let X be the number of voters stated they were in favor of the school district bond…

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Sample proportion=p^=21380z=critical value for 95% confidence interval=1.96n=sample size=380

Q: Out of 156 Nielsen families surveyed about their viewing habits, 43 felt that television was too…

A: We have given that,  Favorable cases (X) = 43 and sample size (N) = 156  Then,  We will find the 99%…

Q: 1. In a recent poll 62 out of 149 randomly chosen students at Allen High School say they plan to buy…

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Q: a recent study of 100 people in Burlingame found that 19 were obese.  Find the 90% confidence…

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Q: In a study of 120 randomly selected families, 50 said they streamed their television content. Find…

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Q: A survey found that out of 900 workers, 150 said they were interrupted by frank phone calls. Find…

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Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: n a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…

A: The given data is appropriate for single proportion confidence interval . because it is a large…

Q: Of 380 randomly selected medical​ students, 21 said that they planned to work in a rural community.…

A: Given that 380 randomly selected medical​ students, 21 said that they planned to work in a rural…

Q: A researcher calculates a 90% confidence interval of (0.24,0.4) for a proportion. What was the…

A: Given :confidence level = 90% confidence interval = (0.24,0.4) p is unknown, so p=0.5 We want to…

Q: in a survey of 2230 adults, 57% thinks that land travel through a tourist bus is much more reliable…

A: Given,sample size(n)=2230sample proportion(p^)=0.57α=1-0.95=0.05α2=0.025Z0.025=1.96       (from…

Q: If a student provided 90% confidence intervals in all ten questions, how many points would we expect…

A: In the given analysis, we have 10 questions and their correct answers. 10 sample responses from 10…

Q: In the Framingham Offspring study 3630 subjects were on anti-hypertensive medication out of 4657…

A: Note: Hi, thank you for the question. As per our company guideline we are supposed to answer only…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: Given , n = 1008 x = 598

Q: Using the accompanying colleges and universities data to find 95% confidence intervals for the…

A: Given:   Liberal Arts Colleges Research Universities 1169 1117 1194 1133 1204 1148 1210…

Q: in a recent poll, 220 people were asked if they liked dogs, and 36% said they did . find the margin…

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Q: The following table shows the results of a survey in which 1017 adults from the United States, 1060…

A: (1)

Q: A researcher asks 600 people if they received a flu vaccine, and 65% said they did. What is the 95%…

A: From the provided information Sample size (n) = 600 65% said they received a flu vaccine that is…

Q: Identify the y-score for a 99% confidence interval if the sample size is 35.

A: We have to find critical value for given data..

Q: In a sample of 1901 patients who underwent a certain type of surgery, 22% experienced complications.…

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Q: An investigative reporter contacts a random sample of hotels, and finds a 95% confidence interval…

A: Given that  The 95% confidence interval for the proportion of hotels in the united states have…

Q: What does the 95% represent in a 95% confidence interval

A: Solution CI=95%

Q: When 328 college students are randomly selected and surveyed, it is found that 122 own a car. Find…

A: We want to find 95% CI for population proportion (p)

Q: A random survey of 36 airline passengers indicates that twelve have never flown before. Find a 95%…

A: We have given that,  Sample size (n) = 36 and favorable cases         (X) = 12 Then,  We Will find…

Q: n our Condor Cafe, the Oxnard College Culinary Program offers the most delicious and affordable…

A: Given that, n=255,x=75

Q: Find the confidence level and a for an 88% confidence interval.

A: Here use confidence level and significance level as alternative of each other

Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: Find a 90% confidence interval for the true proportion of people that eat frog legs, if in a sample…

A: Given, n = 732 p = 0.65 1 - α = 0.90α = 0.1α2 = 0.05   To find, 90% confidence interval for the true…

Q: A poll commissioned by the Center on Addiction and Substance Abuse at Columbia University found that…

A: Given that, X = 1340 N = 2000 98% confidence level

Q: A survey​ asks, "If the husband in a family wants​ children, but the wife decides that she does not…

A: We have to create 99% confidence interval for the population proportion.

Q: A survey of 360 college seniors found that 305 wish they had spent more time studying. Find a 94%…

A: Givensample size(n)=360x=305p^=xn=305360=0.8472confidence interval = 94%

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given : Sample Size, n = 316 Number of successes, x = 112 confidence level,c=0.99…

Q: 12. In a sample of 500 Canadians, 275 say they would rather retire in the US than in Canada.…

A: From the given information, Consider, X be the random variable that denotes the number of people who…

Q: A college administrator is interested in determining the proportion of students who receive some…

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Q: At one large college, 660 out of the 1500 students surveyed said they plan to take another science…

A: Given that,   x=660,n=1500 The sample proportion is, Critical values: By using the standard normal…

Q: In a certain state, a survey of 500 workers showed that 38% belonged to a union.  Find the 93%…

A: Computation of critical value: 1-α=0.93α=0.07α2=0.0351-α2=0.965 The critical value of z-distribution…

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: (a) From the Standard Normal Table, the z value for 99% level is 2.576. The sample proportion is,…

Q: The z value for a 96.6% confidence interval estimate is?

A: z value for a 96.6% confidence interval estimate is?

Q: 1) Jaimie does a study on how many students have passed his classes in the past. He finds that 2739…

A: The random variable students who pass follow normal distribution. The number of successes is 2739.…

Q: A recent survey of 1,000 people found that 90% of Americans support background checks for purchasing…

A:

Q: When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a…

A: The provided information is: It is given that 106 college students (s) own a car among 258 college…

Q: A survey found that out of 800 workers, 150 said they were interrupted by frank phone calls. Find…

A: Given,n=800x=150p^=xnp^=150800=0.18751-p^=1-0.1875=0.8125α=1-0.95=0.05α2=0.025Z0.025=1.96

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Here we need to construct a 95% confidence interval for the population proportion. Here the sample…