Consider a 4-way set associative cache made up of 64-bit words. The number of words per line is 8 and the number of sets 4096 sets. What is the cache size? a) 1 MB b) 10 MB c) 4 MB d) 512 KB

A: To calculate the size of the cache, use the following formula –

A: Cache memory is the faster then RAM. Its size is small as compared to RAM.

A: INTRODUCTION: The cache is a small piece of memory that is part of the CPU and is physically closer…

A: Answer: 1MB

A: Cache size Here the number of sets is 4096 and the number of words per line is 8 per line. The…

A: Given: 4-way set associative cache made up of 64-bit words. number of words per line is 8. number of…

A: Cache size can be calculated using a formula – (No. of sets x Associative number x No. of words per…

A: Given: Consider a 64-bit word-based four-way set associative cache. The number of words each line is…

A: Solution) Formula for cache size- Cache size= No. of words per line x No. of bit word x No. of sets…

A: Required: Consider a 64-bit word-based four-way set associative cache. The number of words each line…

A: Given: Consider a 64-bit word-based four-way set associative cache. The number of words each line is…

A: Given Set Size = 4 Way1 Word = 64 bits = 648 Bytes = 8 BytesLine Size = 8 WordsNumber of Sets =…

A: Answer: I have given answered in the brief explanation

A: Answer: I have given answered in the brief explanation

A: Given: Goal: Find the size of tag bits in the cache.

A: Given: Goal: Find the size of tag bits in the cache.

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A: Total number of blocks inside cache = 4 Cache is 2 way set associative so total number of set inside…

A: The total number of tag bits per set for 4-way set associative cache

A: We are given block size of a cache and main memory latency with bandwidth. We are asked the time…

A: Cache is direct mapped size of cache=32 KB                         = 25 * 210 Bytes…

A: Introduction:Cache Size = 32 KBBlock Size = 32 byteswe have to find out bits needed for indexing of…

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A: Introductions : Given , 4- way set associative cachecache size = 256 KB Block size = 8 word we have…

A: GIVEN:

A: Given : Number of address bits = 10 bits Tag bits = 3 bits Index bits = 3 bits Offset bits = 4…

A: Ans: i) Given, access time =1 ns Hit ratio =0.95, new access time=1.5ns, new hit ratio=0.97 It…

A: In this question, we are given main memory size, cache size, block size. We have to split the…

A: (a) number of blocks = 2^20 / 32 = 2^15 =32*1024=32768so there are 32768 blocks in main memory . (b)…

A: Cache is =1MB; and main memory=256MB;  and the line size is =32bytes The number of…

A: Given, cache -L1          Access time T1=1ns            Hit ratio H1=0.95   After a change in cache,…

A: • The block offset = address % 4•The  index = b(address % 16) / 4c• The tag = baddress / 16c Address…

A: Direct mapping is the simplest strategy, and it maps every block of memory space into only one…

A: Given question has asked to find the Tag field bits value. Information provided in question are as…

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A: Solution : (4)cache memory capacity = 64 kiB = 2^16 BytesBlock size = 128 bytes = 2^7 bytesNumber of…

A: Actually, cache memory is a fast access memory.

A: Given:

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A: Introduction  Given,  2 way set associative cache , block are 4 ,LRU scheme is being used.block…

A: The index for an direct mapped cache is the number of blocks in the cache 2 to the power 6=128. so…

A: Introduction :Given , Single level cache cache access time = 2.5 ns line size = 64 Byte Hit ratio =…

A: Given memory address= thirty two bits of set in a very bit = nine bits cache size is 64kb=216 4 ways…

A: Solution given memory address= 32 bits of set in a bit = 9 bits  cache size is 64kb=216  4 ways set…

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