Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.02 × 10ª N/C as shown in the figure below. 30.0 cm 60.0° 10.0 cm (a) Calculate the electric flux through the vertical rectangular surface of the box. kN • m2/c (b) Calculate the electric flux through the slanted surface of the box. kN • m2/C (c) Calculate the electric flux through the entire surface of the box. | kN · m²/c
Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.02 × 10ª N/C as shown in the figure below. 30.0 cm 60.0° 10.0 cm (a) Calculate the electric flux through the vertical rectangular surface of the box. kN • m2/c (b) Calculate the electric flux through the slanted surface of the box. kN • m2/C (c) Calculate the electric flux through the entire surface of the box. | kN · m²/c
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter24: Gauss’s Law
Section: Chapter Questions
Problem 24.63CP: A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure...
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Step 1
(given)
Electric field (E) in magnitude = 7.02
(a)
Electric flux through the vertical rectangular surface of the box:
Answer:
Electric flux through the vertical rectangular surface of the box = - 2.106 kN m2/C
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