Consider a cube with edge length L immersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux through the closed surface. y L We need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux: Onet Ф, + Ф, + Ф3 + Ф, + 0. 111

University Physics Volume 2
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Chapter6: Gauss's Law
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Problem 25P: A square surface of area 2 cm2 is in a space of uniform electric field of magnitude 103 N/C . The...
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Consider a cube with edge length L immersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux
through the closed surface.
E
L
L
We need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux:
Фnet Ф1 + Ф2 + Ф3 + Фху + Ф
xz Oyz
+
The flux through surface 1 is: 0ı=0.
The flux through surface 2 is:
The flux through surface 3 is: 03
%3D
The flux through the surface on the xy plane is: Oxy
The flux through the surface on the xz plane is: Oxz =
The flux through the surface on the yz plane is: Oyz
Taking the algebraic sum, the net electric flux through the cube is: Onet =
111
Transcribed Image Text:Consider a cube with edge length L immersed in a uniform electric field E along the x-direction as shown in the figure below. Calculate the electric flux through the closed surface. E L L We need to solve for the electric flux through each face of the cube and take the sum to calculate the net electric flux: Фnet Ф1 + Ф2 + Ф3 + Фху + Ф xz Oyz + The flux through surface 1 is: 0ı=0. The flux through surface 2 is: The flux through surface 3 is: 03 %3D The flux through the surface on the xy plane is: Oxy The flux through the surface on the xz plane is: Oxz = The flux through the surface on the yz plane is: Oyz Taking the algebraic sum, the net electric flux through the cube is: Onet = 111
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