Consider a list named myL which contains the elements [1, 2, 3, 4, 5], what will be the final value of myL[0] given the codes below? myL[0] = myL
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- Consider a list named myL which contains the elements [1, 2, 3, 4, 5], what will be the final value of myL[0] given the codes below? myL[0] = myL[-1] + myL[-2] a. 9 b. 5 c. -3 d. 3write a function that will swap tow adjacent elements by adjusting only the links (and not the data) using a single linked listsWrite a program that will take this dictionary: gradePoints = {"A":4,"B":3,"C":2,"D":1,"F":0} and this list: courseList = ["CST 161","Mat 144","ENG 201","PSY 101","HIS 101"] and randomly use elements from each of these lists : gradeList = ["A","B","C","D","F"] creditList = [3,4] and produce a grade point average. Academic average is determined by dividing the total number of qualitypoints earned by the total number of credits taken, whether passed orfailed. The following table is an illustration of this computation:GRADE & QUALITY NUMERICAL POINTSCourse . . . Credits Value Per CourseHIS 101. . . . . .3 C (2) 6PSY 101. . . . . 3 B (3) 9MAT 144. . . . 4 D (1) 4ENG 201. . . . 3 B+ (3.5) 10.5CST 161. . . . . 3 F (0) 0Total credits taken: 16Total quality points earned 29.529.5 divided by 16 results in a 1.8 gradepoint average. Here the gradeList element will be embedded as the key in referencing the grade points. (e.g. gPoints = gradePoints[random gradeList element])…
- Indicate ALL syntax errors of each SML statement and try to correct. Eg. [3, 1=2] answer 1 => type mismatch for a list, 3 has to be boolean.answer 2 => type mismatch for a list, 1=2 has to be int such as 1+2. answer 3 => different type of values, can not be list, tuple instead (3, 1=2) (1) val x = if (hd (false)) then tl ([1,2.0]); (2) val L = [[hd, tl], [tl, hd, hd]];Suppose, alist is a 2-dimensional list that is defined as follows. alist = [ [1], [2,3], [5,6,7] ] Which is the best option to access the last element of the last element of this list (i.e., 7)? Question options: a. alist[ len(alist) - 1 ][len(alist[len(alist) - 1]) - 1] b. alist[ len(alist) - 1 ][len(alist[len(alist) - 1])] c. alist[3][3] d. alist[ len(alist) - 1 ][1]Which of the following is true about linked lists with header and trailer nodes? a) Using header and trailer nodes simplifies the implementation because it eliminates the special cases. b) None of these c) Using header and trailer nodes saves some important information in the header and trailer nodes. d) The header (or trailer) node is the same thing as a head (or tail) reference. e) Using header and trailer nodes can reduce the time complexity of the code.
- Consider the following piece of pseudocode:new DynamicArray dd[1] ← 1d[2] ← 2d[3] ← 3d[2] ← Ød[1] ← ØWhich of the following describes a linked list implementation of this pseudocode?a. Create a new empty linked list, insert a node (with value 1) with next pointer to null, insert a node (with value 2) at the end of list, insert a node (with value 3) at the end of list, remove end node.b. reate a new empty linked list, insert a node (with value 1) with next pointer to null, insert a node (with value 2) at the end of list, insert a node (with value 3) at the end of list, remove middle node, remove first node.c. Create a new empty linked list, insert a node (with value 1) with next pointer to null, insert a node (with value 2) at the beginning of list, insert a node (with value 3) at the end of list, remove end node.Suppose a list contains the final exam results of CSE110, PHY111, and MAT110 of each student in a listed form. Your task is to sort the list based on a course name that will be given by the user and print the names after sorting. For example, a list looks likelst = [ ["Farzad",95,87,91] , ["Mahjabin",92,90,83], ["Sadman",87,92,80], ["Nakhla",85,94,90] ]where for each list, 1st index is name, 2nd index is CSE110, 3rd index is PHY111 and 4th index is MAT110. ===================================================== Hint:create a python function for sorting, then call it everytime instead of rewriting the code. Get the data in the individual lists from the given nested list. ===================================================== Sample InputMAT110 Sample OutputFarzadNakhlaMahjabinSadman**** Write a simple python program that will take this dictionary, the use of fuctions is not permitted: ****** gradePoints = {"A":4,"B":3,"C":2,"D":1,"F":0} and this list: courseList = ["CST 161","Mat 144","ENG 201","PSY 101","HIS 101"] and randomly use elements from each of these lists : gradeList = ["A","B",''B+'',"C","D","F"] creditList = [3,4] and produce a grade point average. Academic average is determined by dividing the total number of qualitypoints earned by the total number of credits taken, whether passed orfailed. The following table is an illustration of this computation:GRADE & QUALITY NUMERICAL POINTSCourse . . . Credits Value Per CourseHIS 101. . . . . .3 C (2) 6PSY 101. . . . . 3 B (3) 9MAT 144. . . . 4 D (1) 4ENG 201. . . . 3 B+ (3.5) 10.5CST 161. . . . . 3 F (0) 0Total credits taken: 16Total quality points earned 29.529.5 divided by 16 results in a 1.8 gradepoint average. Here the gradeList element will be embedded as the key in referencing the…
- Provide full C++ code Building a playlist (of songs) using a linked list and making some operations such as adding songs, removing songs, shuffling them, etc. (Some parts of this lab will closely follow lab 08 - it is imperative that you complete that lab before working on this project). A Node representing a song has the following data members (similar to struct Node of lab 08, except it doesn't have one member for storing data): string uniqueID string songName string artistName int songLength Node* nextNodePtr Your code must have the following three files: Playlist.h - Class declaration for a linked list of Nodes (very similar to lab 08 but with some changes to methods, as described below) with following private data members: private:Node* first;Node* last;int size; Playlist.cpp - Class definition main.cpp - main() function Checkpoint A For checkpoint A, you need to build a playlist (of songs) by readings data members of several songs from a file and printing them. Implement…Write a program that will take this dictionary using python : gradePoints = {"A":4,"B":3,"C":2,"D":1,"F":0} and this list: courseList = ["CST 161","Mat 144","ENG 201","PSY 101","HIS 101"] and randomly use elements from each of these lists : gradeList = ["A","B","C","D","F"] creditList = [3,4] and produce a grade point average. Academic average is determined by dividing the total number of qualitypoints earned by the total number of credits taken, whether passed orfailed. The following table is an illustration of this computation:GRADE & QUALITY NUMERICAL POINTSCourse . . . Credits Value Per CourseHIS 101. . . . . .3 C (2) 6PSY 101. . . . . 3 B (3) 9MAT 144. . . . 4 D (1) 4ENG 201. . . . 3 B+ (3.5) 10.5CST 161. . . . . 3 F (0) 0Total credits taken: 16Total quality points earned 29.529.5 divided by 16 results in a 1.8 gradepoint average. Here the gradeList element will be embedded as the key in referencing the grade points. (e.g. gPoints = gradePoints[random gradeList…get_avg_ratings() takes a 2-D list similar to ratings_db as the parameter and returns a dictionary, where each {key: value} of this dictionary is {a valid movie id: the average rating this movie received by the reviewers}. I will refer to this dictionary as ratings.>>> ratings = get_avg_ratings(ratings_db)>>>> display_dict(ratings)1: 3.922: 3.433: 3.264: 2.365: 3.076: 3.957: 3.198: 2.889: 3.1210: 3.511: 3.6712: 2.4213: 3.1214: 3.83 15: 3.016: 3.9317: 3.7818: 3.719: 2.7320: 2.5 userId,movieId,rating,timestamp1,1,4,9649827035,1,4,8474349627,1,4.5,110663594615,1,2.5,151057797017,1,4.5,130569648318,1,3.5,145520981619,1,4,96570563721,1,3.5,140761887827,1,3,96268526231,1,5,85046661632,1,3,85673611933,1,3,93964744440,1,5,83205895943,1,5,84899398344,1,3,86925186045,1,4,95117018246,1,5,83478790650,1,3,151423811654,1,3,83024733057,1,5,965796031